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natita [175]
3 years ago
9

Explain why 1.55 centimeters is a reasonable answer for the difference in the wingspans of the two butterflies

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0
The difference is referring to subtraction, so the question was most likely something like how much longer is this butterflies wings than this ones. so 4.55 might be one of the lengths and 3 might be the other, so 4.55 - 3 is 1.55.
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E vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). The perimeter of ∆ABC is units, and its area is square units.
UNO [17]

We can use the distance formula to calculate perimeter: \sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2} = Distance


From A to B: √232

From B to C: 10

From C to A: √52


10 + √232 + √52 = 10 + 2√58 + 2√13


Perimeter = 10 + 2√58 + 2√13 units


For Area we can use matrices, but since one of the sides is horizontal, we can just calculate with distance formula and area of triangle formula.


The area of a triangle formula is 1/2(h x b)

h=height

b=base


So the height is 6 and the base is 16. (I graphed it.)

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3 years ago
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Solve the following inequality algebraically
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The table below shows function r, which represents the total cost of a field trip to the science museum, in dollars, if n studen
mafiozo [28]

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Can I please get some help
Aleksandr [31]

Answer:

a. 1.76

b. 2.5

Step-by-step explanation:

You have the following formula given in the exercise:

t=\frac{\sqrt{100-h}}{4}

a. If the object is 50 feet above the ground, you can identify that the value of the variable "h" would be the following:

h=50

Then, knowing that value, you can substitute it into the given formula and then evaluate in order to calculate the time in seconds for the object to be 50 feet above the ground.

This is:

t=\frac{\sqrt{100-50}}{4}\\\\t=1.76

b. When the object reaches the ground, the value of "h" is:

h=0

Therefore, substituting this value into the formula and evaluating, you get that time (in seconds) it takes to the object reaches the ground is:

t=\frac{\sqrt{100-0}}{4}\\\\t=2.5

7 0
3 years ago
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