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3 years ago

Hannah has a biased coin.

1 answer:

muminat3 years ago

7 0

Look at it this way:

When you flip a coin, the probability of it landing with EITHER side showing
is 100%.

This leads us to the rule ...

The sum of the probabilities of
all possible outcomes is 100%.

For a coin: (probability of heads) plus (probability of tails) = 100%.

That just says: We're 100% sure that the coin will land with either
heads or tails up.

An "honest" coin gets heads 50% of the time and tails the other 50%.

But if the coin is all bent and squashed and has a feather stuck to
one side and a wad of gum on the other side so that it comes up
heads 70% of the time, then the coin isn't 'honest'. But it still has to
land EITHER heads OR tails, so the sum of the probabilities is still 100%.

So the probability of heads is 30%.

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An automated assembly line produces 840 units per hour. At the same production rate, how many units could be produced in 45

WARRIOR [948]

Answer:

The 630

Step-by-step explanation:

i took the test on usa test prep

6 0

3 years ago

Find the distance between the points (-8,-11) and (14,-11).

coldgirl [10]

Answer:

Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

Step-by-step explanation:

The answer is provided above.

Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

Hope this helps.

6 0

3 years ago

Read 2 more answers

Find the H.C.F of x² - 3x ,x² - 9

krek1111 [17]

X^2-3x = x(x-3)
x^2-9 = x^2 - 3^2 = (x-3)(x+3)
HCF = x-3

7 0

3 years ago

Read 2 more answers

Simplify the expression: 5^2 - 3 * 6 A)7 B)24 C)132 D)144

kow [346]

Answer:

Step-by-step explanation:

5^2 = 5 x 5 = 25

3 x 6 is 18

25 - 18 is 7

also, use PEMDAS

5 0

3 years ago

Read 2 more answers

Sam entered three functions into a graphing calculator, y1 = x + 2, y2 = x2 + 2, and y3 = 2x. A portion of the table created by

V125BC [204]

For this case we have the following functions:
$y1 = x + 2

y2 = x ^ 2 + 2

y3 = 2 ^ x$

When x = 0 we have:
For y1:
$y1 = 0 + 2

y1 = 2$
For y2:
$y2 = 0 ^ 2 + 2

y2 = 0 + 2

y2 = 2$
Therefore, we have to:
$y1 = y2
$

When x = 5 we have:
For y2:
$y2 = 5 ^ 2 + 2

y2 = 25 + 2

y2 = 27$
For y3:
$y3 = 2 ^ 5

y3 = 32$
Therefore, we have to:
$y2 \ \textless \ y3
$

When x = -1 we have:
For y1:
$y1 = -1 + 2

y1 = 1$
For y2:
$y2 = (-1) ^ 2 + 2

y2 = 1 + 2

y2 = 3
$
For y3:
$y3 = 2 ^ {-1}

y3 = 1/2

y3 = 0.5$
Therefore, we have to:
$y3 \ \textless \ y1 \ \textless \ y2
$

Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2

4 0

4 years ago