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3 years ago

True or false: Climate of an area is established without studying long term weather patterns PLS HELP THIS IS SCIENCE NOT MATH

1 answer:

4 0

True I’m pretty sure: Climate can change without studying weather patterns, you don’t need to study them for climate to be established. If i’m wrong sorry

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You want to purchase a house in 10 years. You estimate the cost will be $184,500.00. You want to make a 20% down payment and pay

Ilia_Sergeevich [38]

Use the formula of the future value of annuity ordinary and solve for pmt
First deducted the amount of down payment
184,500−184,500×0.20=147,600

Pmt=147,600÷(((1+0.085
÷12)^(12×10)−1)÷(0.085÷12))
=784.53 per month

5 0

3 years ago

PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the

stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4 True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10) is not one of the vertices of the shaded region of the set of inequalities.

3 0

3 years ago

Using the transformation T: (x,y) —> (x+2, y+1), find the distance CB

pshichka [43]

Answer:

The distance between CB is $\sqrt[]{10}$

Step-by-step explanation:

Recall that the transformation T consists of a translation of 2 units to the right and 1 unit up. Then, T preserves distances(which means that it keeps distances between points the same as before applying the transformation). Then, distance CB is the sames as distance C'B'. We will use the distance formula: if we have points (x,y), (z,w) then the distance between them is given by

$\sqrt[]{(x-z)^2+(y-w)^2}$

In our case we have that C'=(0,3), B'=(3,4). Then, the distance between them is

$\sqrt[]{(3-0)^2+(4-3)^2}= \sqrt[]{10}$

5 0

3 years ago

Jason's monthly practice time on the piano is 35 hours. This month, he has practiced 8.5 hours in week 1, 12 hours in week 2, an

krok68 [10]

Given :

Monthly practice time , T=35 hours .

This month, he has practiced 8.5 hours in week 1, 12 hours in week 2, and 5.5 hours in week 3.

To Find :

Many more hours of practice time does Jason need to complete .

Solution :

Number of hours he practice in week 1 , $t_1=8.5\ hours$ .

Number of hours he practice in week 2 , $t_2=12\ hours$ .

Number of hours he practice in week 3 , $t_3=5.5\ hours$ .

Now , number of hours left is :

$t=T-t_1-t_2-t_3\\\\t=35-(8.5+12+5.5)\ hours\\\\t=8\ hours$

Hence , this is the required solution .

8 0

3 years ago

A model rocket is launched from the top of a building. The height (in meters) of the rocket above the grown is given by h(t)=-6t

Iteru [2.4K]

Answer:

47.5 Meters

Step-by-step explanation:

Find where the derivative changes from positive to negative (local maximum)

h(t)= $-6t^2+30t+10$

h'(t)= $-12t+30$

Find where the derivative equals zero

Theres no spot where the derivative wont exist because its a polynomial.

-12t=-30

t= $\frac{5}{2}$

Ill stop here because this is a parabola opening down and this is the only spot where there will be a horizontal tangent line so this is the x-coordinate of the vertex. AKA you don't need to test positive and negative on both sides.

Now plug into original equation

h(2.5)= $-6(2.5)^2+30(2.5)+10$

=-37.5+75+10

=47.5

5 0

3 years ago