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Kobotan [32]
3 years ago
13

Burning gasoline in a car affects the

Mathematics
1 answer:
pshichka [43]3 years ago
8 0
Burning gasoline in a car affects the "Enviorment". Hope this helped!
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A car can be rented for $60 per week plus $0.40 per mile. How many miles can be driven if you have at most $300 to spend for wee
Step2247 [10]

Answer: 600 Miles

Step-by-step explanation:

We start off with $300.

We have to spend $60 to rent the car.

300 - 60 = $240

The remaining $240 can be spent on miles.

$240/0.40 = 600 Miles

6 0
3 years ago
(-7x^2+3) + (4x^2+2x-1);<br> Find the sum or difference.
ivann1987 [24]
(-7x² + 3) + (4x² + 2x - 1)

-7x² + 3 + 4x² + 2x - 1          

(-7x² + 4x²) + (3 - 1) + 2x      collect like terms

-3x² + 2x + 2     

hope this helps, God bless!
4 0
4 years ago
Which expression is equivalent to 30m2+12m+18?? Please help ASAP !
ANTONII [103]

Answer:

c) 6(5m2+2m+3)

Step-by-step explanation:

Given expression = 30m2 + 12m + 18

The simplified form can be calculated by taking GCF

The GCF of 30m2, 12m and 18 is = 6

Therefore, the expression becomes

(6*5m2 + 6*2m + 6*3)

=> 6(5m2+2m+3) so option c is correct

7 0
4 years ago
PLEASE HURRY!50 POINTS ANS BRAILIEST
densk [106]

Answer:

A:

The decreasing value of car 1 can be represented by an exponential function and car 2 by a linear function

B:

Car 1: f(x) = 18500(0.94)^{x}

Car 2: f(x) = 18500 - 1000x

C:

Car 1 would be $10600.40 after 9 years

Car 2 would be $9500.00 after 9 years

There is a significant difference of $1100.40 in value.

Step-by-step explanation:

f(x) = ar^{x}\\f(0) = a = 18500\\f(x) = 18500r^{x}\\f(1) = 18500r = 17390\\r = \frac{17390}{18500} = 0.94\\f(x) = 18500(0.94)^{x}

7 0
4 years ago
A point is selected at random inside the given figure.
Westkost [7]
The answer is/was 2/15. 

I hope this helps/helped anybody now or in the future.
3 0
3 years ago
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