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ANTONII [103]
3 years ago
9

Bearings Problem Solving Question:

Mathematics
1 answer:
Lynna [10]3 years ago
7 0

9514 1404 393

Answer:

  a) 123.4°

  b) 3.3 km

Step-by-step explanation:

In (N, E) coordinates, Boat 1 is located relative to the lighthouse at ...

  2(cos(60°), sin(60°)) = (1.0, 1.732) . . . . . km

Boat 2 is located at ...

  3(cost(340°), sin(340°)) = (2.819, -1.026) . . . . . km

So, relative to Boat 2, Boat 1 is located at ...

  (1, 1.732) -(2.819, -1.026) = (-1.819, 2.758) . . . . . km

This is at a bearing of ...

  arctan(2.758/-1.819) = 123.4°

and a distance of ...

  √(1.819² +2.758²) ≈ 3.304 . . . . . km

a) Boat 2 would need to travel on a bearing of 123.4°.

b) Boat 2 would need to travel 3.3 km.

_____

<em>Additional comment</em>

We use (North, East) coordinates so we don't have to do the mental gyrations necessary to translate to and from (E, N) coordinates. The latter would correctly orient a map relative to the X-Y Cartesian plane. The former are equivalent to flipping the map over and looking at it from the back side. This is a "rigid transformation", so angles and distances remain unchanged.

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I think the answer is 30x+330>50x

Step-by-step explanation:

for the option A it was slightly changed,

cause the $30 was deposited by <em><u>helen</u></em> not <em><u>Vince.</u></em>

<em><u>so </u></em><em><u>check </u></em><em><u>that </u></em><em><u>well</u></em>

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What is the solution set for this inequality?
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Step-by-step explanation:

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2 years ago
On Monday Godswill ate some grapes. On Tuesday he
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Answer: He ate 8 grapes on Monday.

Step-by-step explanation:

Let be "x" the number of grapes Godswill ate on Monday.

You know that he ate 6 more grapes than he had on Monday. This can be expressed with:

x+6

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The NCAA is interested in estimating the difference in mean number of daily training hours for men and women athletes on college
hammer [34]

Answer:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data given

\bar X_M = 2.7 represent the sample mean for men

\bar X_F = 2.4 represent the sample mean for women

s_M = 0.3 represent the sample deviation for men

s_F = 0.4 represent the sample deviation for women

n_M = 10 sample size of male

n_F =10 sample size of women

The confidence interval is given by:

(\bar X_M -\bar X_F) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_M}+\frac{1}{n_F}}   (1)

The polled variance can be calculated with this formula:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

For a confidence of 95% the value for the significance is \alpha=1-0.95=0.05 and \alpha/2 = 0.025, the degrees of freedom are given by:

df = n_M + n_F -2= 10+10-2=18

And the critical value can be calculated with the following formula in excel: "=T.INV(1-0.025,18)" and we got t_{\alpha/2}=2.1

Now we can replace into the confidence interval:

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

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