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Radda [10]
3 years ago
15

What are the integer solutions to the inequality below?

%20%5C%202x%2B1" id="TexFormula1" title="3\leq 3x-4\ \textless \ 2x+1" alt="3\leq 3x-4\ \textless \ 2x+1" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Rudik [331]3 years ago
7 0

Given:

The compound inequality is:

3\leq 3x-4

To find:

The integer solutions for the given compound inequality.

Solution:

We have,

3\leq 3x-4

Case 1: 3\leq 3x-4

3+4\leq 3x

\dfrac{7}{3}\leq x

2.33...\leq x             ...(i)

Case 2: 3x-4

3x-2x

x                  ...(ii)

Using (i) and (ii), we get

2.33...

The integer values which satisfy this inequality are only 3 and 4.

Therefore, the integer solutions to the given inequality are 3 and 4.

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Answer:

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Step-by-step explanation:

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To find the amount of soil needed for the next of planting we will subtract the amount of potting soil used on the first day (\frac{25}{2}) from amount of total potting soil (\frac{125}{4}).

\text{Amount of potting soil needed for second day}=\frac{125}{4}-\frac{25}{2}

\text{Amount of potting soil needed for second day}=\frac{125}{4}-\frac{25\times 2}{2\times2}

\text{Amount of potting soil needed for second day}=\frac{125}{4}-\frac{50}{4}

\text{Amount of potting soil needed for second day}=\frac{75}{4}

\text{Amount of potting soil needed for second day}=\frac{75}{4}=18\frac{3}{4}

Therefore, the group will need 18\frac{3}{4} pounds of potting soil to finish their work.            

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