The vertex angle bisector divides the triangle into two congruent right triangles. The sine of half of the vertex angle will be half of the base divided by the side (from the definition of the sine of an angle). Then the total vertex angle is ...
α = 2×arcsin(3.5/5) ≈ 88.9°
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Using the Law of Cosines, the vertex angle can be found as
arccos((7^2 -5^2 -5^2)/(-2*5*5)) = arccos(1/50) ≈ 88.9°
Answer:the answer is c
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given expression is 
.
Now we need to find the cube root of given expression .
![\sqrt[3]{27a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D)
![=\sqrt[3]{3*3*3a^{4*3}}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%2A3%2A3a%5E%7B4%2A3%7D%7D)
![=\sqrt[3]{3^3\left(a^4\right)^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%5E3%5Cleft%28a%5E4%5Cright%29%5E3%7D)
![=\sqrt[3]{\left(3a^4\right)^3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B%5Cleft%283a%5E4%5Cright%29%5E3%7D)
Since cube root and cube are opposite operations of each other. So they will cancel each other.
Hence correct choice is the last choice .
Answer:
2 tickets
Step-by-step explanation:
To be the same they must equal each other.
4.50 + 0.65x = 0.40x + 5
isolate the variable
subtract 4.50 from both sides
0.65x = 0.40x + 0.50
subtract 0.40x from both sides
0.25x = 0.50
divide both sides by 0.25
x = 0.50 ÷ 0.25
x = 2
Let x be the unknown number
x×55%=121
x=121÷55%
x=220
So 121 is 55% of 220
