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3 years ago

What does 2 3/4 and 3 1/8 look like as a decimal?

Mathematics

2 answers:

Zina [86]3 years ago

8 0

Answer:for 2 3/4 as a decimal is 0.75 and for 3 1/8 its 3.125

318 is 3.125 as a decimal and 312.50% as a percentage.

Step-by-step explanation:Hope this helped u also may i plz have brainlist?

elena55 [62]3 years ago

4 0

Answer:

2 3/4 = 2.75

3 1/8 = 3.125

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A shooting star forms a right triangle with the Earth and the Sun, as shown below:

frez [133]

The positions of the sun, earth and shooting star form a right angled triangle, where distance between earth and sun is 'y', and the angle 'x°' is given

Now, in a right angled triangle using trigonometry, we can determine a side of the triangle is one of the sides and one of the angles is known

Here, if we use cos x = $\frac{Base}{Hypotenuse}$ we can determine the distance between the shooting star and the sun. This can be done because we know that the base is 'y', the angle is x° and the hypotenuse represents the distance between the sun and the shooting star

Note: cos values for each x are definite.

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3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

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3 years ago

PLEASE HELP IMAGE ATTACHED!!! the area of this parallelogram is 120mm^2. Find the value of X

Marta_Voda [28]

The area of a parallelogram is the base times the height so:

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x=12mm

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Please help, YOU WILL GET 50 POINTS

netineya [11]

Answer:

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