URGENT!
1 answer:
You might be interested in
Answer:
Option C. Independent Variable: time, Dependent Variable: net profit
Graph starts out rising and starts falling mid-year. At the beginning of 2006 it is at the minimum value and begins rising again before staying at a fairly constant rate for the remainder of the year
Step-by-step explanation:
In this problem
Let
x------> the time
y-----> the net profit
we know that
The independent variable is the time (variable x)
The dependent variable is the net profit (variable y)
see the attached figure to better understand the problem
Answer:
We have the system:
y > x^2 - 1
y < (-1/2)*x + 3
To find the solutions of this set we need to graph the solutions range of both sets, and see the intersection between these solution ranges.
How we do it?
Start with the first one.
First, we graph the equation:
y = x^2 - 1
Now because we are using the symbol ">" means that y is smaller than the thing at the right, then the graph of the equation will be with a dashed line (which means that the points on the line are not solutions) and we will shade all the region above the line
For the other inequality we do the same:
First we graph:
y = (-1/2)*x + 3
And because we have the symbol "<" we again use a dashed line, but this time we will shade all the region below the line.
Once we shaded both regions, the region where we have both shades will be the region of solutions for the system of inequalities.
You can see the graph below.
