F(a)=a^3-10a^2+28a-17 at a=6
1 answer:
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We know that
x²+px−35=0-------> <span>has one root that is equal to 7
so
substitute x=7 in the equation
</span>7²+p*7−35=0
49+p*7−35=0
14+p*7=0
p=-14/7------> p=-2
the answer Part a) is
t<span>he value of the coefficient p is -2
</span>
Part b) <span>Find the other root
</span>x²+px−35=0-----> x²-2x−35=0
<span>
using a graph tool-------> to resolve the second order equation
see the attached figure
the other root is
x=-5
the answer part b) is
</span> the value of the other root is -5<span>
</span>
x²+px−35=0-------> <span>has one root that is equal to 7
so
substitute x=7 in the equation
</span>7²+p*7−35=0
49+p*7−35=0
14+p*7=0
p=-14/7------> p=-2
the answer Part a) is
t<span>he value of the coefficient p is -2
</span>
Part b) <span>Find the other root
</span>x²+px−35=0-----> x²-2x−35=0
<span>
using a graph tool-------> to resolve the second order equation
see the attached figure
the other root is
x=-5
the answer part b) is
</span> the value of the other root is -5<span>
</span>
Hello here is a solution :
