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ASHA 777 [7]
3 years ago
5

Plzzz help me im in a crisis lol jk but plz

Mathematics
1 answer:
makkiz [27]3 years ago
6 0

Answer:

Lateral : 21

surface : 39

Step-by-step explanation:

I think that this is correct. :)

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Three cubes of the same metal, whose edges are 6, 8, 10 cm are meltedand formed into a single cube. Find the diagonal of the sin
allochka39001 [22]

Answer: 12√2 cm

<u>Step-by-step explanation:</u>

Cube 1: V = 6³ = 216

Cube 2: V = 8³ = 512

Cube 3: <u>V = 10³ = 1000</u>

New Cube: V = 1728

1728 = s³

12 = s

So, each side of the new cube is 12 cm.

Use Pythagorean Theorem to find the length of the diagonal:

12² + 12² = diagonal²

144 + 144 = diagonal²

288 = diagonal²

√288 = diagonal

12√2 = diagonal


3 0
3 years ago
Find the equivalent expression using the same basses (61*31)^8
lisabon 2012 [21]

Answer:

52026353283901

Step-by-step explanation:


4 0
3 years ago
Point A is located at (1, 5), and point M is located at (−1, 6). If point M is the midpoint of segment AB, find the location of
sashaice [31]
Ans: B=(-3, 7)

Step by step explanation:
7 0
3 years ago
The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

hence,

\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
3 years ago
Jane bought 5 apples at $120 each. She sells them to John to make a profit of 10%. What is the selling price of each apple?​
Alex787 [66]

Answer:

she resells each apple for $132

Step-by-step explanation:

I multiplied 120 by 0.1 to find how much she would be marking up the price of each apple. I got the answer of $12. So then I added that $12 to $120 and got the new price of $132.

I checked my work I swear it's correct

hope this helps chu <3

5 0
3 years ago
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