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Elina [12.6K]
2 years ago
9

Arrange the computers in the order fastest to slowest: Minicomputer, Supercomputer, Personal Computer and Mainframe.

Computers and Technology
1 answer:
Likurg_2 [28]2 years ago
6 0

Answer:

supercomputer, mainframe, personal computer, minicomputer

Explanation:

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Insert the appropriate functions in the Summary Statistics section of the worksheet: cells H18:H22. Format the payments with Acc
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Answer:

Explanation:

If we want to insert the appropriate functions, we can know the operation, for example, it could be a sum, multiply, average or only divide, but if we want to apply for a format number like accounting number, we must go to the tab home and the section number, we can change the format number, an accounting or even text format.

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How can I cancel my subscription I try to go to my account setting and the only thing that pops up is terms of use and change co
Sati [7]

If the only trying that appears is terms of use and change country, that means you are a free user and not a paying subscriber.

So there is no actual subscription to cancel.

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2 years ago
class llist { private: record * start; char filename[16]; int readfile(); int writefile(); record * reverse(record * ); void cle
Sophie [7]

Answer:

See Explaination

Explanation:

#include <cstdlib>

#include <iostream>

#include <iomanip>

#include <fstream>

#include <string>

#include <sstream>

using namespace std;

struct Person

{

string name;

string addr;

string phone;

string id;

};

const int MAX_SIZE = 8;

void addData(Person list[], int& size);

void dispData(const Person list[], int size);

void delData (const Person list[], int size);

void saveFile(const Person list[], int size);

void openFile(Person list[], int& size);

char getMenuResponse();

int main(int argc, char *argv[])

{

Person contactList[MAX_SIZE];

int numOfRecs = 0;

bool run = true;

do

{

cout << "Address Book - " << numOfRecs << " Number of Contacts" << endl;

switch ( getMenuResponse() )

{

case 'A': addData(contactList, numOfRecs); break;

case 'D': dispData(contactList, numOfRecs); break;

case 'T': delData(contactList, numOfRecs); break;

case 'O': openFile(contactList, numOfRecs); break;

case 'S': saveFile(contactList, numOfRecs); break;

case 'Q': run = false; break;

default : cout << "That is NOT a valid choice" << endl;

}

} while (run);

cout << endl << "Program Terminated" << endl;

return EXIT_SUCCESS;

}

void addData(Person list[], int& size)

{

Person tmp;

char response;

char str[256];

if (size < MAX_SIZE) {

system("cls");

cout << "Enter Contact Information" << endl << endl;

cout << "Name: ";

cin.getline(str, 256, '\n');

tmp.name = str;

cout << endl;

cout << "Address: ";

cin.getline(str, 256, '\n');

tmp.addr = str;

cout << endl;

cout << "Phone Number: ";

cin.getline(str, 256, '\n');

tmp.phone = str;

cout << endl;

cout << "E-mail id Address: ";

cin.getline(str, 256, '\n');

tmp.id = str;

cout << endl;

cout << "Add Contact to Address Book? (y/n) ";

cin >> response;

if (toupper(response) == 'Y')

list[size++] = tmp;

} else {

cout << "Sorry, Address Book is currently full." << endl;

system("pause");

}

system("cls");

}

void dispData(const Person list[], int size)

{

system("cls");

if(size < 1)

{

cout << "Nothing to display" << endl;

} else {

cout << "Contacts :" << endl << endl;

cout << fixed << setprecision(2);

cout << "Contact Name Address Phone No. ID" << endl;

cout << left;

for (int i = 0; i < size; i++)

{

cout << setw(10) << list[i].name << right

<< setw(10) << list[i].addr<<right

<< setw(10) << list[i].phone<<left

<< setw(15) << list[i].id<<left<<endl;

}

cout << right << setw(3) << size;

cout << " Contacts"<< endl;

}

system("PAUSE");

system("cls");

}

void delData(const Person list[],int size) {

vector<Person> :: iterator vItr = Contact.begin();

while (vItr != Contact.end() )

{

if (vItr->Name == Name)

{

vItr = Contact.erase (vItr);

break;

}

else

vItr++;

}

void saveFile(const Person list[], int size) {

string fileName;

ofstream outfi;

cout<<"Enter file name: ";

getline(cin,fileName);

outfi.open(fileName.c_str());

if (!outfi.fail()) {

system("cls");

cout << "Saving Address Book to the disc ";

for(int i = 0; i < size; i++) {

outfi << list[i].name << ';'

<< list[i].addr<< ';';

if (i < size-1) outfi << endl;

}

cout << endl << size << " Address Book in the disc." << endl;

outfi.close();

system("PAUSE");

system("cls");

}

else {

cout << "ERROR: problem with file" << endl;

system("PAUSE");

system("cls");

}

}

void openFile(Person list[], int& size)

{

ifstream infi("AddressBook.txt");

string str;

stringstream strstrm;

if (!infi.fail()) {

system("cls");

cout << "Reading Address Book from the disc ";

size = 0;

while(!infi.eof() && size < MAX_SIZE)

{

getline(infi, str, ';');

list[size].name = str;

getline(infi, str, ';');

strstrm.str(""); strstrm.clear();

strstrm << str;

strstrm >> list[size].addr;

}

cout << endl << size << " read contacts from the disc." << endl;

system("PAUSE");

system("cls");

}

else {

cout << "ERROR :file not accepted" << endl;

system("PAUSE");

system("cls");

}

}

char getMenuResponse()

{

char response;

cout << endl << "take chioce" << endl

<< "(A)dd contact, (D)isplay contact0, (O)pen File, (S)ave File, (Q)uit" << endl

<< "> ";

cin >> response;

cin.ignore(256, '\n');

return toupper(response);

}

8 0
2 years ago
Write down a description of how a magnetic had drive works
Rus_ich [418]

Answer:

This is how a magnetic hard drive works

Explanation:

The hard drive contains a spinning platter with a thin magnetic coating. A "head" moves over the platter, writing 0's and 1's as tiny areas of magnetic North or South on the platter. To read the data back, the head goes to the same spot, notices the North and South spots flying by, and so deduces the stored 0's and 1's.

Hope it helps pls mark as brainliest

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What is the portrait mode ?
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