Answer:
The answer is 39.
Step-by-step explanation:
I will divide the range into 5 division to count palindromes more easy.
<u>From 10 to 100:</u>
11
There are only 1 number exist that at least the digit 1 appears once.
<u>From 100 to 1000:</u>
<u>Section 1:</u>
_1_ (e.g. 212)
There are be 9 numbers exist that at least the digit 1 appears once from above number structure.
<u>Section 2:</u>
1_1 (e.g. 121)
There are be 10 numbers exist that at least the digit 1 appears once from above number structure.
<u>From 1000 to 10000:</u>
<u>Section 1:</u>
1__1 (e.g. 1221)
There are be 10 numbers exist that at least the digit 1 appears once from above number structure.
<u>Section 2:</u>
_11_ (e.g. 2112)
There are be 9 numbers exist that at least the digit 1 appears once from above number structure.
Since the population is going to increase by a certain percentage, we have to add to the percentage to keep the original population.
Now, convert the percentage into a decimal. You can do this by moving the decimal place two places to the left.
Now, just multiply that by .
RX is + XS is the hypotenuse of the right triangle RTS, then:
(RX + XS)^2 = (RT)^2 + (ST)^2
=> (4+9)^2 = (RT)^2 + (ST)^2
=> 13^2 = (RT)^2 + (ST)^2 .....equation (1)
Triangle RTX and XST are also right triangles.
RT is the hypotenuse of RTX and ST is the hypotenuse os SXT.
Then, (RT)^2 - (RX)2 = (TX)^2 and (ST)^2 - (SX)^2 = (TX)^2
=> (RT)^2 - (RX)^2 = (ST)^2 - (SX)^2
=> (RT)^2 - (ST)^2 = (RX)^2 -(SX)^2
=> (RT)^2 - (ST)^2 = 4^2 - 9^2 = 16 - 81 = - 65
=> (ST)^2 - (RT)^2 = 65 ..........equation (2)
Now use equations (1) and (2)
13^2 = (RT)^2 + (ST)^2
65 = (ST)^2 - (RT)^2
Add the two equations:
13^2 + 65 = 2(ST)^2
2(ST)^2 =178
(ST)^2 = 234/2 = 117
Now use (ST)^2 - (SX)^2 = (TX)^2
=> (TX)^2 = 117 - 81 = 36
=> (TX) = √36 = 6
Answer: 6
Answer:
Step-by-step explanation:
Given table is:
i.e. when term number, t = 1, number of triangles (n) = 1
when term number, t = 2, number of triangles (n) = 3
when term number, t = 3, number of triangles (n) = 5
when term number, t = 4, number of triangles (n) = 7
If we closely look at the pattern, number of triangles (n) in each row are 1 lesser than twice of term number (t).
i.e. for
Therefore, the number of triangles in the nth term will be given as:
Answer:
y=3/10;X=-7/10
Step-by-step explanation:
put y=x+1 into where you find y.
solve for X which is -7/10
and put -7/10 into the second equation and solve for y. which is also =3/10