The area of the rectangle:
A = Length x Width = JK x KL = 36 cm²
If JK ≥ 4 cm, we have to prove that KL ≤ 9 cm.
Answer:
Assume that a. KL > 9 cm.
Then the area of rectangle JKLM is greater than b. 36 cm²,
which contradicts the given information that c. side is at least 4 cm long.
So the assumption must be false. Therefore, d. KL ≤ 9 cm.
Range: the set of all y-values of a graph or equation.
Y-intercept: the y-value where the graph intersects the y-axis.
Domain: the set of all x-values of a graph or equation.
X-intercept: the x-values where the graph intersects the x-axis.
Hope this helps! :)
Answer:
y = 1/9
Step-by-step explanation:
(-2, y) = (x, y)
y = 3^x
y = 3^(-2)
y = 1/9
Therefore y = 1/9
Answer:
Area = 16π
Step-by-step explanation:
Area of a circle = πr^2
= 64π
= sqrt64
r = 8 because 8 × 8 is 64
Radius = 8
Now, use the circumference equation:
= 2πr
= 2π(8)
= 16π
