How to find rapidly the coordinates of Q:
since Q is the center of gravity of the triangle ABC, so we have the following vector relationship
vecQA +vecQB +vecQC =<span>vec0
</span><span>vecQA=(x-3, y+2)
</span><span>vecQB=(x-1, y+5)
</span><span>vecQC=(x-7, y+5)
</span><span>vec0=(0, 0)
</span>
so, vecQA +vecQB +vecQC =<span>vec0 is equivalent to
</span>x-3 +x-1+x-7 =0, and y+2+y+5+<span>y+5=0 so 3x-11=0 implies x=11/3
</span><span>and 3y+12=0 implies y=-12/3
finally the </span><span>the coordinates of point Q is (11/3, -4)</span><span>
</span>
Answer:
Tickets: $78
snacks: $21
total: $99
Step-by-step explanation:
expensive movies.
Answer:
B)
Step-by-step explanation:
225x^2 - 1=
(15x)^2 - 1^2=(*)
(15x-1)(15x+1)
A^2 - B^2 =(A-B)(A +B)............. (*)
First you must multiply the number by the percent. (19*27= 513)
Then you divide the answer by 100, or move decimal two places to the left. (513/100= 5.13)
Then round to the nearest whole number (5.13 is approximately 5)
Therefore 19%of 27 = 5
:)
