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natta225 [31]
3 years ago
7

PLEASE HELP QUICK

Physics
1 answer:
Reika [66]3 years ago
5 0

Answer: 270 km

Explanation:

3 cm/80 km :: 10 cm/(x)km

cross multiply

3x = 80(10)

x = 800/3 = 266.66666... ≈ 270 km

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An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
Arisa [49]

Explanation:

Distance = (intial speed)X(Time) + 1/2(acceleration)X(Time) [Third equation of motion]

As initial speed is zero, therefore;

Distance = 1/2(acceleration)X(Time)

              = 1/2 (6 X 15)

              = 1/2 (90)

              = 45 meters

Hence, the object traveled 45 meters.

4 0
4 years ago
The energy a sled has when you pull it back up a hill is best described as
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The answer is d because you are using energy to pull the sled back up, which is mechanical energy
5 0
3 years ago
Radio communications were severely Distributed last week And the local newspaper says that solar activity is to blame . Which ty
Juliette [100K]

Answer:

Solar Flares and Prominences

Explanation:

    The sun is source of light and heat energy and it supports life on earth because sun is the primary source of energy. But sun is also a star and is a glowing ball of hot gases mostly hydrogen and helium. There are so many activity that takes place on surface of sun. But the two activity solar flare and prominences affect the radio communication.

Solar Flare  are electromagnetic energy built up in the sun atmosphere .These energy travel with the speed of light and affect outer atmosphere of earth. These increased level of X rays and ultraviolet rays ions the layer of ionosphere which becomes superionised. thus causing destructive interference.

The radio waves travel in ionosphere and  frequently collide with electron lose energy and completely blackout.

Prominence is defined as gaseous cloud of calcium,hydrogen and other gases floating above sun chromosphere and emit violently particularly near sunspots sometimes travel through space and affect radio communication.

8 0
4 years ago
An electron, moving south, enters a magnetic field of certain strength. Because of this field the electron curves upward. What i
e-lub [12.9K]

Answer: The magnetic field points to the west.

Explanation:

If we take the plane as:

North = positive y-axis

East = positive x-axis.

We have that the electron is moving south, so the velocity of the electron can be written in vector form as:

V = (0, -v, 0)

Now, when the electron interacts with the magnetic field, the electron moves upwards.

We know that the interaction between an electron and a magnetic field is:

F = q*VxB

So we have that this force acts on the z-direction.

Now, to solve this we can use the righ hand rule.

First, we point wit our hand to the direction of the velocity (negative y-axis) now, we want that our thumb points up (the direction of the force) so the side where our palm faces is the direction of the field B.

But, remember that an electron has a negative charge, so the actual equation is:

F = -q*VxB

So the magnetic field actually points in the opposite direction of our palm, to the west.

Now, we can also solve it mathematically as:

F = (0, 0, f) = -q*(0, -v,0)x(a, b, c)

where B = (a, b, c) is the vector of the magnetic field.

     (0, 0, f) = -q*(-v*b -0, -0 + 0, 0 -(- a*v)) = -q*(-v*b, 0, a*v)

then we have that b must be equal to zero, and that:

f = -q*a*v

and f is positive, then we have:

a = -(f/q*v)

then the vector of the magnetic field is:

B = (-(f/q*v), 0, 0)

so it points in the negative x-axis, that is the West, as we found earlier.

4 0
4 years ago
Two charges, -20 C and +4.7 C, are fixed in place and separated by 3.0 m. a. At what spot along a line through the charges is th
Pani-rosa [81]

The zero net electric field point is at a point that is 0.98 m away from 4.7C charge.If a 14C charge is placed at this point then, force acted on the charge placed at this point is equal to zero.

Explanation:

Let at A both net electric field is zero then

At A ,E1=E2

E1=k*Iq1I / (d+x)^2

E2=k*Iq2I /x^2

Equating both

6 0
4 years ago
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