Taking into account the definition of density, the density of the rock is 3.6583 g/mL.
<h3>Definition of density</h3>
Density is defined as the property that matter has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
The expression for the calculation of density is:
density= mass÷ volume
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
<h3>Density of the rock</h3>
In this case, you know that:
- Mass= 88.53 g
- Volume of the rock= Volume after place the rock in the water - Volume of water= 74.2 mL - 50 mL= 24.2 mL
Replacing in the definition of density:
density of rock= 88.53 g÷ 24.2 mL
Solving:
<u><em>density of rock= 3.6583 g/mL</em></u>
In summary, the density of the rock is 3.6583 g/mL.
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Answer:
a) Shadow distance
10 cm in front of the mirror.
b) Zoom in the shadow
The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.
c) The nature of the shadow
The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.
Explanation:
English Translation
Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:
a) Shadow distance
b) Zoom in the shadow
c) The nature of the shadow
Solution
The mirror equation is given as
(1/f) = (1/v) + (1/u)
f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm
v = image distance = ?
u = object distance = 10 cm
We can then calculate the shadow' s distance from the mirror thus
(1/5) = (1/v) + (1/10)
(1/v) = 0.2 - 0.1 = 0.1
v = (1/0.1) = 10 cm
b) Zoom in the shadow
Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.
c) The nature of the shadow
Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.
Hope this Helps!!!
The velocity, or speed, of light is determined by the density of the medium it is traveling through. The more dense a medium is, the slower light will travel. As a result, your answer should be something like this:
1. Solid
2. Liquid
3. Gas
4. Vacuum
Answer:
0.26seconds
Explanation:
Impulse is the product of force and time
Impulse =Force * Time
Given
Impulse = 67Ns
Force = 257N
Required
Time
From the formula;
Time = Impulse/Force
Time = 67/257
Time = 0.26s
Hence the amount of time is 0.26seconds
Answer:
0.51 m
Explanation:
From the question,
Applying coulomb's law,
F = kqq'/r²....................... Equation 1
Where F = Electrostatic force, q = magnitude of the first charge, q' = magnitude of the second charge, r = distance between the two charges, k = coulombs constant
making r the subject of the equation
F×r² = kqq'
r² = kqq'/F
r = √(kqq'/F).................. Equation 2
Given: F = 4.2×10⁻⁴N, q = q' = 1.1×10⁻⁷C, k = 9×10⁹ Nm²/C²
Substitute these values into equation 2
r = √(9×10⁹×1.1×10⁻⁷×1.1×10⁻⁷/4.2×10⁻⁴)
r = √(1.1×1.1×9/4.2)(10⁹×10⁻⁷×10⁻⁷×10⁴)]
r = √(2.59×10⁻¹)
r = √(0.259)
r = 0.508
r ≈ 0.51 m