Option B The thickness of the central portion of a thin conveying lens can be determined very accurately by using a micrometer screw gauge.
<h3>What can be measured using a micrometer screw gauge?</h3>
One micrometer of thickness can be measured with a micron micrometre screw gauge. A Use of Micrometer Screw Gauge as like example Upon turning the screw of the micrometer screw gauge four times, a 2 mm space is covered.
<h3>What purposes does a micrometer serve?</h3>
A tool known as a micrometer is used to measure solid objects’ lengths, thicknesses, and other dimensions precisely and linearly.
<h3>What is the micrometer screw gauge’s SI unit?</h3>
The SI symbol m is also known as a micron, which is an SI-derived unit of length equaling 1106 meters, where 106 is the SI standard prefix for the prefix “micro-.” A micrometer is one-millionth of a meter.
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Passive transport occurs thanks to diffusion, diffusion is the reason passive transport is able to travel throughout the cell membrane.
The frequency of rotation of Mars is 0.0000113 Hertz.
<u>Given the following data:</u>
- Period = 1 day and 37 minutes.
To find the frequency of rotation in Hertz:
First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.
<u>Conversion:</u>
1 day = 24 hours
24 hours to minutes =
×
=
minutes
![1440 + 37 = 1477 \; minutes](https://tex.z-dn.net/?f=1440%20%2B%2037%20%3D%201477%20%5C%3B%20minutes)
1 minute = 60 seconds
1477 minute = X seconds
Cross-multiplying, we have:
× ![1477](https://tex.z-dn.net/?f=1477)
X = 88620 seconds
Now, we can find the frequency of rotation of Mars by using the formula:
![Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}](https://tex.z-dn.net/?f=Frequency%20%3D%20%5Cfrac%7B1%7D%7BPeriod%7D%5C%5C%5C%5CFrequency%20%3D%20%5Cfrac%7B1%7D%7B88620%7D)
<em>Frequency </em><em>of rotation</em> = <em>0.0000113 Hertz</em>
Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.
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Answer:
2 charges of electron (2C)
Explanation:
I = Q/t
2 = Q/1
Q = 2×1= 2C
Q = 2 charge of electron
F = 750 N (Force)
d = 10 m (displacement
)
t = 25 s (time)
L = ? (Mechanical work
) = (Energy)
P = ? (Power)
Solve:
L = F × d = 750 × 10 = 7500 Joules
P = L / t = 7500 / 25 = 300 Watts