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BlackZzzverrR [31]
3 years ago
10

Estimate how many raindrops would fall on 1 acre plot during a 1 inch rainfall​

Physics
1 answer:
Tom [10]3 years ago
5 0

Answer:

1,580,088,782,700

Explanation:

There are 90,021 drops of water in one gallon, so multiplying all together. Roughly 1,580,088,782,700 drops of water will fall. Or about 1 1/2 trillion drops.

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A 3kg horizontal disk of radius 0.2m rotates about its center with an angular velocity of 50rad/s. The edge of the horizontal di
Lyrx [107]

Answer:

D

Explanation:

From the information given:

The angular speed for the block \omega = 50 \ rad/s

Disk radius (r) = 0.2 m

The block Initial velocity is:

v = r \omega \\ \\  v = (0.2  \times 50) \\ \\  v= 10 \ m/s

Change in the block's angular speed is:

\Delta _{\omega} = \omega - 0 \\ \\ = 50 \ rad/s

However, on the disk, moment of inertIa is:

I= mr^2 \\ \\ I = (3 \times 0.2^2) \\ \\ I = 0.12 \ kgm^2

The time t = 10s

∴

Frictional torques by the wall on the disk is:

T = I \times (\dfrac{\Delta_{\omega}}{t}) \\ \\ = 0.12 \times (\dfrac{50}{10})  \\ \\ =0.6 \ N.m

Finally, the frictional force is calculated as:

F = \dfrac{T}r{}

F= \dfrac{0.6}{0.2} \\ \\ F = 3N

8 0
3 years ago
What is a car’s acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s? 10 m/s2 –15 m/s2 15 m/s2 5 m/s2
Vesna [10]

Answer:

5 m/s²

Explanation:

Acceleration = change in speed/time taken

20-5=15

15/3= 5 m/s²

6 0
2 years ago
What will happen if you increse the amplitude of a drum hit
expeople1 [14]

The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases.  As the amplitude of the sound wave increases, the intensity of the sound increases. Sounds with higher intensities are perceived to be louder.

5 0
3 years ago
44. The maximum horizontal distance a boy can throw a ball is 50 m. Assume he can throw with the same initial speed at all angle
tensa zangetsu [6.8K]

The maximum height reached by the ball thrown by the boy is determined as 12.5 m.

<h3>Angle of the projection</h3>

The angle of projection of the ball is calculated as follows;

R = u²sin2θ/g

  • at maximum range, θ = 45 degrees

50 =  u²/9.8

u² = 50 x 9.8

u² = 490

u = 22.14 m/s

<h3>Maximum height of the ball</h3>

H = u²sin²θ/2g

H = (22.14² x (sin45)²)/(2 x 9.8)

H = 12.5 m

Thus, the maximum height reached by the ball thrown by the boy is determined as 12.5 m.

Learn more about maximum height here: brainly.com/question/12446886

#SPJ1

5 0
2 years ago
Consider the acceleration of an object that is undergoing simple harmonic motion. Is this acceleration zero or nonzero?
GaryK [48]

Answer:

Non-zero

Explanation:

For a simple harmonic motion, the restoring force is given by

F = -kx (1)

where

k is the spring constant

x is the displacement of the system with respect to the equilibrium position

According to Newton's second law, the acceleration of the system is given by

a = F/m (2)

where

m is the mass of the system

So if we substitute (1) into (2) we find

a = -kx/m

so the acceleration is directly proportional to the displacement. Since the value of the displacement  in a simple harmonic motion constantly changes, the acceleration changes as well, so it is non-zero (apart from the instant where the displacement is zero, x = 0, when the acceleration is also zero)

8 0
3 years ago
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