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ivanzaharov [21]
3 years ago
9

The specific heat of gold is 0.031 calories/gram°C and the specific heat of silver is 0.057 calories/gram°C. If equal amounts of

each metal are exposed to equal heating, which will heat up faster?
The silver will heat up almost twice as fast.
The gold will heat up almost twice as fast.
They will heat up at the same rate.
It is impossible to tell.
Physics
1 answer:
Nady [450]3 years ago
3 0
The gold will heat up almost twice as fast. The specific heat of a metal tells us just how much calories is needed to change the temperature of a metal by 1 degree celsius. Given this, the smaller the specific heat of a metal, the faster it will heat up.
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What is the sequence of energy transformations from the moment the ball is dropped to the moment the board is bent to its maximu
Mila [183]

Answer:

B

Explanation:

Transformation of energy involves conversion of energy from one form to another for example our movement around involves the conversion of chemical energy stored in the food we eat to other forms of energy such as kinetic energy for the movement, electrical energy in the neurons for impulses and others

The ball posses gravitational potential energy since it is held at a displacement to the ground ( zero point) and when released, the gravitational potential energy is converted to kinetic energy which leads to the fall of the ball until it is at zero displacement to the earth. The board likewise when bent to its maximum extent stored elastic potential energy as a result of the partial displacement of its constituent particle provided it is  not stretch beyond its elastic limit which can lead to deformation of the board and the elastic potential energy lost.

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4 years ago
When air is blown across the top of an open
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8 0
4 years ago
The fastest pitched baseball was clocked at 47 m/s. Assume that the pitcher exerted his force (assumed to be horizontal and cons
Eduardwww [97]

Answer:

Following are the solution to the given points:

Explanation:

For point a:

Find the schematic of the empty body and in attachment. Upon on ball during the pitch only two forces act:

The strength of the pitcher F is applied that operates horizontally. Its gravity force acting on an object is termed weight, which value is where m denotes mass, and g the acceleration of gravity.

For point b:

160.2\  N

First, they must find that ball's acceleration. You can use the SUVAT equation to achieve that

where

v = 47\  \frac{m}{s} \\\\u = 0 \\\\a =?\\\\d = 1.0 \ m \\\\

Solving for a,

a=\frac{v^2-u^2}{2d}=\frac{47^2-0}{2(1.0)}=1104.5 \ \frac{m}{s^2}

Calculating the mass:

m = 145 g = 0.145 kg

Calculating the force:

F=ma=0.145 \times 1104.5= 160.2 \ N

 For point c:

0.195 times the pitcher's weight

m = 84 \ kg \\\\g = 9.8\ \frac{m}{s^2}\\\\

Solving for W:

W=84 \times 9.8= 823.2 \ N

Now the force of Part B could be defined as the fraction of the mass of the pitcher:  

\frac{F}{W}=\frac{160.2}{823.3}=0.195

4 0
3 years ago
Answers please!!!!!!!!!!!!!!!!
kaheart [24]
I only know #2 and #4.
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4 years ago
What is the period of a wave with a speed of 20.0 m/s and a frequency of 10.0 Hz?
Delvig [45]

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