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Fittoniya [83]
3 years ago
5

Ethan and Daniel are required to read a 300-page novel for their literature class. The number of pages read by Ethan and Daniel

so far during a 5-day period is shown.
Ethan: 39, 29, 60, 29, 45

Daniel: 34, 29, 54, 43, 24

1. What is the mean number of pages read per day by Ethan?



2. What is the mean number of pages read per day by Daniel?
Mathematics
1 answer:
Allisa [31]3 years ago
8 0
1. mean number read by Ethan is  (39+ 60 + 29 + 29 + 45) / 5 = 202/5 = 40.4

2.  Mean number by Daniel  = (34 + 29 + 54 + 43 + 24) = 184 / 5 = 36.8
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So for this you need to find 15% of 60. There are a few ways to do this but I prefer to do it like this.

First, find 10% of 60. This can be found by dividing 60 by 10, because 100%/10% is 10.

This gives 10%=6

5% is half of 10%, so divide your answer for 10% (6), by 2.

This gives 5%=3

We needed 15%, so we add our 10% and 5% together, to get 9.

15% of 60 is 9, meaning there are 9 puppies.

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a = 10000

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When purchasing bulk orders of​ batteries, a toy manufacturer uses this acceptance sampling​ plan: Randomly select and test 56 b
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Answer:

98.1% chance of being accepted

Step-by-step explanation:

Given:

sample size,n=56

acceptance condition= at most 2 batteries do not meet specifications

shipment size=7000

battery percentage in shipment that do not meet specification= 1%

Applying binomial distribution

<h3>P(x)=∑ᵇₐ=₀ (n!/a!(n-a)!)p^a (1-p)^(n-a)</h3>

In this formula, a is the acceptable number of defectives;

 n is the sample size; 

p is the fraction of defectives in the population.  

Now putting the value

a= 2

n=56

p=0.01

\frac{56!}{0!\left(56-0\right)!}\left(0.01\right)^0\:\left(1-0.01\right)^{\left(56-0\right)} + \frac{56!}{1!\left(56-1\right)!}\left(0.01\right)^1\:\left(1-0.01\right)^{\left(56-1\right)} +\:\frac{56!}{2!\left(56-2\right)!}\left(0.01\right)^2\:\left(1-0.01\right)^{\left(56-2\right)}

=0.56960+0.32219+0.08949

After summation, we get 0.981 i.e. a 98.1% chance of being accepted.  As this is such a high chance, we can expect many of the shipments like this to be accepted!

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Answer:

The answer is $5450 per month

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