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Answer:
The number of teachers who teach physics n(P) = 12
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given that the number of teachers who teach mathematics or physics
n(MUP) = 20
Given that the number of teachers who teach mathematics
n(M) = 12
Given that the number of teachers who teach both mathematics and physics
n(M∩P) = 4
<u><em>Step(ii):-</em></u>
By using n(A∪B) = n(A) + n(B) - n(A∩B)
n(M∪P) = n(M) +n(P) - n(M∩P)
20 = 12 + n(P) - 4
20 -12 +4 = n(P)
n(P) = 12
<u><em>Final answer:-</em></u>
The number of teachers who teach physics n(P) = 12
Solve for c :
x⁴ + cx² + 100 = 0
cx² = -(x⁴ + 100)
c = - (x⁴ + 100)/x²
If x = 0, the right side is undefined and c would have no solution.
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The distance between the numbers increases by two every interval
for example, the difference between 1 and 2 is 1, if you add 2 you get 3, and the difference between 2 and 5 is 3
hope this helped!
