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adoni [48]
2 years ago
11

PLZ HELP. choices below 8th grade math. attachment below THX.

Mathematics
2 answers:
Hitman42 [59]2 years ago
5 0
$68
Y = X — 2
.................
SOVA2 [1]2 years ago
4 0
$68

~~~~~~~~~~

y= x - 2

since you subtract 2 to get with the coupon, you would just add 2 for without the coupon.
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Add the 2 1/2 to the other side to get rid of to isolate the x
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1/(√2+√3)-√4 pls explain i dont understand
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Hey there!

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=−2−√2+√3

(Decimal: -1.682163)

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What value of x will make the equation true
adell [148]

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7 0
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Read 2 more answers
Rodrigo is planning on buying a new home. The total amount he needs to borrow is $299,132. The bank offered Rodrigo a 18 year lo
Flauer [41]

Answer:

13402

Step-by-step explanation:

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(Excel works great with this and will solve it for you, use the PMT function and insert the numbers provided.  It will show a (-) but that is because a positive PV is placed.)

3 0
2 years ago
fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q
RoseWind [281]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\

Let F is a value of the content so, the value is:

\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\

Now, we calculate the tooling value:

\to p[\frac{C}{F}]

using the baues therom:

\to p[\frac{C}{F}] =  \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }  

            =  \frac{ 0.17  \times 0.14 }{0.55 \times 0.15 + 0.28 \times 0.12 + 0.17 \times 0.14  } \\\\=  \frac{0.0238}{0.0825 + 0.0336 + 0.0238} \\\\=  \frac{0.0238}{0.1399} \\\\=0.1701

7 0
3 years ago
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