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Answer: The correct option is fourth, i.e., SSS.
Explanation:
First write the name of vertices as shown below,
From the figure we can say that in triangle DAB and triangle BCD,
In both triangle the sides BD is common, so,
Since three sides of triangles DAB and triangle BCD are same so by the SSS property of congruent triangle we can conclude that the triangle DAB and triangle BCD are congruent.
Therefore the fourth option is correct.
Answer:
13 and 14.
Step-by-step explanation:
So we have two consecutive integers.
Let's call the first integer a.
Since the integers are consecutive, the other integer must be (a+1) (one more than the last one).
We know that the sum of the greatest integer (or a+1) and twice the lesser integer (a) is 40. Therefore, we can write the following equation:
The first term represents the greatest integer. The second term represents 2 times the lesser integer. And together, they equal 40.
Solve for a. Combine like terms:
Subtract 1 from both sides. The 1s on the left cancel:
Divide both sides by 3:
Therefore, a or the first integer is 13.
And the second integer is 14.
And we can check:
14+2(13)=14+26=40