3 years ago

Please help with #6.3 ! ( I will mark brainliest )

1 answer:

3 0

Function 2 is changing more quickly because while plotting the given points on the graph is starts from 11 then goes low
Therefore answer to ur question is function 2.... Hope this helps u....!!

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Answer:

Option A. $10\ units^{2}$

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

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W is the width of rectangle

we have

$A(-3,1),B(-2,-1),C(2,1),D(1,3)$

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

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$A(-3,1),D(1,3)$

substitute in the formula

$AD=\sqrt{(3-1)^{2}+(1+3)^{2}}$

$AD=\sqrt{(2)^{2}+(4)^{2}}$

$AD=\sqrt{20}$

$AD=2\sqrt{5}\ units$

Find the distance AB

$A(-3,1),B(-2,-1)$

substitute in the formula

$AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}$

$AB=\sqrt{(-2)^{2}+(1)^{2}}$

$AB=\sqrt{5}$

$AB=\sqrt{5}\ units$

Find the area

$A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}$

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