For this, I got the equation (X+3)^2-2 or X^2+6X+7. I used this method:
First I set up an equation (X+H)^2-K, where (K, H) is the vertex. All we have to do is find where the graph reaches its minimum value (because it opens upwards), then find the x-coordinate that lies there, which is (-2,3). Substituting these value in for H and K, we get the equation <span>(X+3)^2-2 or simplified X^2+6X+7.
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Answer:
4
Step-by-step explanation:
set
constrain:
Partial derivatives:
Lagrange multiplier:
4 equations:
By solving:
Second mathod:
Solve for x^2+y^2 = 7, x^3+y^3=10 first:
The maximum is 4
Answer:
nike its observational
Step-by-step explanation:
Answer:
C = 87.92 mm
General Formulas and Concepts:
<u>Symbols</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Geometry</u>
Circumference Formula: C = πd
- <em>C</em> is circumference
- <em>d</em> is diameter
Step-by-step explanation:
<u>Step 1: Define</u>
Diameter <em>d</em> = 28 mm
<u>Step 2: Solve</u>
- Substitute in variables [Circumference Formula]: C = 3.14(28 mm)
- [Circumference] Multiply: C = 87.92 mm