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Nuetrik [128]
3 years ago
9

An atom has no electrical charge because _____.

Physics
1 answer:
Firdavs [7]3 years ago
6 0

Answer:

The no. of protons is equal to the no. of electrons.

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Suppose a spacecraft orbits the moon in a very low, circular orbit, just a few hundred meters above the lunar surface. The moon
Finger [1]

Spacecraft will be moving in 1700 m/s.

Option C

<h3><u>Explanation: </u></h3>

The diameter of the moon is 3500 km and the free fall acceleration at the surface is given as  1.6\ \mathrm{m} / \mathrm{s}^2

The radius will be half of the diameter of the moon that can be written as:  

r_{\text {moon }}=1.75 \times 10^{6}

By the application of the equation for orbit speed, we get  

\begin{aligned}&v_{\text {orbit}}=\sqrt{r \times q}\\&v_{\text {orbit}}=\sqrt{\left(1.75 \times 10^{6}\right) \times\left(1.6\ \mathrm{m} / \mathrm{s}^{2}\right)}\\&v_{\text {orbit}}=1700\ \mathrm{m} / \mathrm{s}\end{aligned}

5 0
3 years ago
A laser emits light of frequency 4.74 x 1014 hz. what is the wavelength of the light in nm?
Ulleksa [173]
<span>Use this formula:Wavelength=c/v, where c is the speed of light, and v the frequency. 6.33 X 10^-7=3 X 10^8/v v=3 X 10^8/6.33 X 10^-7 v=4.74 X 10^14 Hertz,</span>
5 0
3 years ago
Which factor indicates the amount of charge on the source charge?
Elina [12.6K]
B. The number of field lines on the source charge.
4 0
3 years ago
Read 2 more answers
The average distance of the planet mercury from the sun is 0.39 times the average distance of the earth from the sun. How long i
Stels [109]

Answer:

T_1=0.24y

Explanation:

Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

(\frac{T_1}{T_2})^2=(\frac{D_1}{D_2})^3

Where T_1 and T_2 are the orbital periods of Mercury and Earth respectively. We have D_1=0.39D_2 and T_2=1y. Replacing this and solving for

T_1^2=T_2^2(\frac{D_1}{D_2})^3\\T_1^2=(1y)^2(\frac{0.39D_2}{D_2})^3\\T_1^2=1y^2(0.39)^3\\T_1^2=0.059319y^2\\T_1=0.24y

5 0
3 years ago
What is the resistance of 1.0 m of a solid cylindrical metal cable having a diameter of 0.40 inches and a resistivity of 1.68 ×
Dahasolnce [82]

Given;

redistivity =1.68/100000000W.m

diameter =0.40in

=0.01016m

length =1m

resistance =?

redistivity =resistance×area/lenght

restance=resistivity × length /area

so, resistance =1.6535/1000000 ohmn

8 0
3 years ago
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