Answer:

Explanation:
We can assume this problem as two concentric spherical metals with opposite charges.
We have also to take into account the formulas for the electric field and the capacitance. Hence we have

Where k is the Coulomb's constant. Furthermore, by taking into account the expression for the potential and by integrating
![dV=Edr\\\\V=\int_{R_1}^{R_2}Edr=-\int_{R_1}^{R_2}\frac{kQ}{r^2}dr\\\\V=kQ[\frac{1}{R_2}-\frac{1}{R_1}]](https://tex.z-dn.net/?f=dV%3DEdr%5C%5C%5C%5CV%3D%5Cint_%7BR_1%7D%5E%7BR_2%7DEdr%3D-%5Cint_%7BR_1%7D%5E%7BR_2%7D%5Cfrac%7BkQ%7D%7Br%5E2%7Ddr%5C%5C%5C%5CV%3DkQ%5B%5Cfrac%7B1%7D%7BR_2%7D-%5Cfrac%7B1%7D%7BR_1%7D%5D)
Hence, the capacitance is
![C=\frac{1}{k[\frac{1}{R_2}-\frac{1}{R_1}]}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B1%7D%7Bk%5B%5Cfrac%7B1%7D%7BR_2%7D-%5Cfrac%7B1%7D%7BR_1%7D%5D%7D)
but R1=a and R2=b

HOPE THIS HELPS!!
Based on the given displacement vs time graph, the object is at rest at a time interval of: B. 2 to 3 seconds
<h3>What is a
displacement vs time graph?</h3>
A displacement vs time graph can be defined as a type of graph that is used to graphically represent the distance traveled (covered) or displacement experienced by an object from its starting position with respect to the time when it has started moving.
In Science, a physical object being at rest simply means that the position of the object is not changing with respect to time. Thus, both the slope and velocity of the physical object would be equal to zero when it is at rest.
Between 0 to 2 seconds on the given displacement vs time graph (see attachment), this object is traveling at a constant, positive velocity. However, at a time interval of 2 to 3 seconds the object is at rest.
Read more on displacement vs time graph here: brainly.com/question/19144777
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Answer:As an equation, the tangential velocity is the distance, 2π r, divided by the time, T. Thus, A point on the circle moves a distance 2π r in a time T. We can extend our equation by looking at a few ideas. These concepts include the angular speed, ω, and the frequency, f. The angular speed, ω, is a speed of rotation.
Explanation:
i know