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kow [346]
3 years ago
6

An external, frictionless pin only prevents rotation. A. True B. False

Physics
1 answer:
stepan [7]3 years ago
7 0

Answer:

False

Explanation:

The roller displacement at an external, friction less rotation pin is found to be zero as it has a support which is no-yielding but still provides rotation to the object where as at an external pin a shear force is present and the moment is absent which means that at an external pin its not the rotation that is absent but its the moment which comes out to be zero.

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calculate the diameter of a silver wire of length 75cm , which is extended by 1.85mm when a 10kg mass is suspended from it's end
sdas [7]

Answer:0.8\ mm

Explanation:

Given

length of wire l=75\ cm

change in length \Delta l=1.85\ mm

mass of wire m=10\ kg

Young's modulus for silver E=7.9\times 10^{10}\ N/m^2

load on wire F=mg

F=10\times 9.8=98\ kg

change in length is given by

\Delta l=\dfrac{Pl}{AE}

Where A=area of cross-section

A=\dfrac{Pl}{\Delta lE}

A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}

A=\dfrac{73.5}{14.615\times 10^{7}}

A=5.029\times 10^{-7}\ m^2

also wire is the shape of cylinder so cross-section is given by

A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2

\Rightarrow d^2=\dfrac{5.029\times 10^{-7}\times 4}{\pi }

\Rightarrow d^2=64.02\times 10^{-8}

\Rightarrow d=8\times 10^{-4}\ m

\Rightarrow d=0.8\ mm

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3 years ago
4. Which scientist proposed the theory that the Moon formed from fission? (5 points)
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The answer would be B, George Darwin :)
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3 years ago
What is a magnetic field’s shape?
Agata [3.3K]

Answer:

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3 years ago
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