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Kruka [31]
3 years ago
10

How much of the circle is shaded? Write your answer as a fraction in simplest form.

Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Answer:

\frac{7}{15} of the circle is shaded.

Step-by-step explanation:

Circle Consists of 3 parts.

First part is the shaded part.

Now Given:

Portion of Second part = \frac{1}{5}

Also Given:

Portion of Third part = \frac{1}{3}

We need to find the portion of shaded part.

Solution:

We know that 1 whole circle is divided in 3 parts.

So Portion of shaded part will be equal to 1 circle minus Portion of Second part minus Portion of third part.

framing in equation form we get;

Portion of shaded part = 1-\frac{1}{5}-\frac{1}{3}

Now taking LCM for making the denominator common we get;

Portion of shaded part =\frac{1\times15}{15}-\frac{1\times3}{5\times3}-\frac{1\times5}{3\times5} = \frac{15}{15} - \frac{3}{15}-\frac{5}{15} = \frac{15-3-5}{15} = \frac{7}{15}

Hence We can say that \frac{7}{15} of the circle is shaded.

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From the graph, we get that:

The domain is (-4,4).

The function has no zeros.

The function is positive in the interval (-4, 0].

The function is negative in the interval (0,4).

------------------------------------

The domain of a function is the set that contains all the possible input values. In a graph, it is the values of the x-axis, that is, the horizontal axis.

In this question, the values of x are in the interval of (-4,4) thus, the domain is (-4,4).

The zeros are the values of x for which y = 0, that is, the values of x where the function crosses the horizontal axis. In this question, the function does not cross the horizontal axis, thus, it has no zeros.

The function is positive when the graph is above the horizontal axis. In this question, it is in the interval (-4,0].

The function is negative when the graph is below the horizontal axis. In this question, it is in the interval (0,4).

A similar problem is given at brainly.com/question/24493729

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Answer:

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Step-by-step explanation:

Because you only round up if the number next to the 1st decimal place is greater than 5, you just drop the 4 and keep 31.2.

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Step-by-step explanation:

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