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zhannawk [14.2K]
3 years ago
10

Noel has rowing lessons every 5 days and guitar lessons every 6 days. If he had both lessons on the last day of the previous mon

th, when will he have both lessons on the same day of the current month?
Mathematics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

Since every 30 days  he  wil have both lessons on the same day , and  he already  had both lessons on the last day of the previous month, that means that the day 30  the current month   he  wil have both lessons on the same day (It may be the last day if the month has 30 days or it may not be the last day if the month has 31 days)

Step-by-step explanation:

Lets find the least common factor of 5 and 6

Multiples of 5

5  10  15  20  35  30  35  40......

Multiples of 6

6  12  18  24  30 36  

LCF of 5 and 6 = 30

Every 30 days  he  wil have both lessons on the same day

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3 years ago
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your grade in Class varies directly with how many hours you study. you study for 3 hours and get a 60. What grade would you get
wel

To do this question you can use proportions.

3/60 is simplified to 1/20.

This shows that if you study 1 hour you get a 20. So to find the answer you multiply each side by 4.5, this means that if you study 4.5 hours you get a 90.

8 0
3 years ago
1) A rectangular storage container with an open top is to have a volume of 15 m 3 . The length of its base is four times the wid
My name is Ann [436]

9514 1404 393

Answer:

  a) V = 4w²h

  b) SA = 4w² +10wh

  c) SA = 4w² +37.5/w

  d) C = 40w² +225/w

Step-by-step explanation:

The relevant formulas are ...

  V = LWH

  base area = LW

  lateral area = H(2(L+W))

__

a) The length is 4 times the width, so the volume is ...

  V = (4w)(w)(h)

  V = 4w²h

__

b) The total surface area is the sum of the base area and the lateral area:

  SA = base area + lateral area

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__

c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...

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  h = 15/(4w²)

Then the surface area is ...

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__

d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:

  C = 10(4w²) +6(37.5/w)

  C = 40w² +225/w

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3 years ago
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