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ruslelena [56]
3 years ago
8

What are the coordinate pairs of AB?

Mathematics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

A = -3, B = 7

Step-by-step explanation:

yw hope it helps! :)

You might be interested in
Michele correctly solved a quadratic equation using the quadratic formula as shown below.
Fofino [41]

Answer:

The original equation must have been:

7x^{2} -5x-2=0

Step-by-step explanation:

A quadratic equation is in the form of :

ax^{2} +bx+c=0

And it is solved in the form of :

x=\frac{-b+\sqrt{b^{-4ac} } }{2a} and x=\frac{-b-\sqrt{b^{-4ac} } }{2a}

Now the given equation is :

x=\frac{-(-5)+-\sqrt{(-5)^{2} -4(7)(-2)} }{2(7)}

We can see that here;

a = 7

b = -5

c = -2

So, the original equation must have been:

7x^{2} -5x-2=0

5 0
3 years ago
At a particular food processing factory, a machine is supposed to package mixed nuts such that each package contains 50% peanuts
Tamiku [17]

Answer: It is the proper ratio.

Step-by-step explanation: All of the numbers added together would make the 500 mixed nuts that it mentioned which would be 100%

271 plus 108 plus 78 plus 43 = 500

6 0
3 years ago
Question Help The circumference of the hub cap of a tire is 73.54 centimeters. Find the area of this hub cap. Use 3.14 for it. U
Archy [21]
See attached picture

8 0
2 years ago
PLEASE HELP ASAP<br><br> Find the value of x. Then, find the measure of each angle.
andriy [413]

Answer:

x = 16°

H = 46°

I = 55°

J = 39°

Step-by-step explanation:

Since the whole figure is 180°

Deduct 180 by the numbers mentioned above in order to find x.

180 - 2 - 9 - 9 = 160

3x + 4x + 3x = 10x

10 x = 160

x = 160 ÷ 10 = 16

Since we know what x is, we can find all the angles in the figure.

Angle at H = 3 x 16 - 2 = 46°

Angle at I = 4 x 16 - 9 = 55°

Angle at J = 3 x 16 - 9 = 39°

5 0
3 years ago
Read 2 more answers
A rectangular package sent by a postal service can have a maximum combined length and girth (perimeter of a cross sectio) of 108
Morgarella [4.7K]

Answer:

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

Step-by-step explanation:

This is a optimization with restrictions problem.

The restriction is that the perimeter of the square cross section plus the length is equal to 108 inches (as we will maximize the volume, we wil use the maximum of length and cross section perimeter).

This restriction can be expressed as:

4x+L=108

being x: the side of the square of the cross section and L: length of the package.

The volume, that we want to maximize, is:

V=x^2L

If we express L in function of x using the restriction equation, we get:

4x+L=108\\\\L=108-4x

We replace L in the volume formula and we get

V=x^2L=x^2*(108-4x)=-4x^3+108x^2

To maximize the volume we derive and equal to 0

\dfrac{dV}{dx}=-4*3x^2+108*2x=0\\\\\\-12x^2+216x=0\\\\-12x+216=0\\\\12x=216\\\\x=216/12=18

We can replace x to calculate L:

L=108-4x=108-4*18=108-72=36

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

4 0
3 years ago
Read 2 more answers
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