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jasenka [17]
3 years ago
10

John sells plain cakes for $8 and decorated cakes for $12. On a particular day, John started with a total of 100 cakes, and sold

all but 4. His sales that day totaled $800.
He sold ___
plain cakes and ____
decorated cakes that day.
Mathematics
2 answers:
qaws [65]3 years ago
6 0

x+ y =  96   →     y = 96 - x     (1)

And the price per plain cake * the number he sold + price of the decorated cake * the number he sold = total sales

So

8x + 12y = 800    (2)

Subbing (1) into (2), we have that

8x + 12 (96 - x)  = 800   simplify

8x + 1152 - 12x  = 800       

-4x + 1152 = 800    subtract 1152 from both sides

-4x  = -352     divide both sides by -4

x = 88   = the number of plain cakes he sold

And 96 - x =  96 - 88  = 8   = the number of decorated cakes he sold

VikaD [51]3 years ago
3 0

Answer:

He sold 88 plain cakes and he decorated 8 cakes.

Step-by-step explanation:

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At the fast food restaurant, four cheeseburgers and five small fries have a total of 2,310 calories. Three cheeseburgers and two
Svetlanka [38]

<u><em>Answer:</em></u> <em><u>290 calories in a cheeseburger and 230 calories in fries.</u></em>

<em><u>x = calories in a cheeseburger</u></em>

<em><u>y =  calories in an order of small fries</u></em>

<em><u>Four cheeseburgers and five small fries have 2,310 calories. Therefore</u></em>

<em><u>4x + 5y = 2310       (1)</u></em>

<em><u>Three cheeseburgers and two small fries have 1,330 calories. Therefore</u></em>

<em><u>3x + 2y = 1330        (2)</u></em>

<em><u>Equations (1) and (2) model the given situation.</u></em>

<em><u>To solve, multiply (1) by 2, and multiply (2) by 5 to obtain</u></em>

<em><u>  8x + 10y = 4620          (3)</u></em>

<em><u>15x + 10y = 6650          (4)</u></em>

<em><u>Subtract (3) from (4).</u></em>

<em><u>7x = 2030</u></em>

<em><u>x = 290</u></em>

<em><u>From (1), obtain</u></em>

<em><u>5y = 2310 - 4*290 = 1150</u></em>

<em><u>y = 230</u></em>

<em><u> x = 290, y = 23</u></em>

<u><em>Hope this helps!</em></u>

<u><em>:)</em></u>

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