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siniylev [52]
3 years ago
5

At a particular food processing factory, a machine is supposed to package mixed nuts such that each package contains 50% peanuts

, 20% hazelnuts, 20% cashews, and 10% pecans. A randomly-selected can containing 500 of these mixed nuts was found to have 271 peanuts, 108 hazelnuts, 78 cashews, and 43 pecans. At the 5% significance level, determine whether the machine is mixing the nuts in the proper ratio.
Mathematics
1 answer:
Tamiku [17]3 years ago
6 0

Answer: It is the proper ratio.

Step-by-step explanation: All of the numbers added together would make the 500 mixed nuts that it mentioned which would be 100%

271 plus 108 plus 78 plus 43 = 500

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You start at (5, -3). you move up 8 units. where do you end?
djyliett [7]

Answer:

(5,5)

Step-by-step explanation:

You draw a graph and put an x where (5, -3) is and then from that point, you go up by 8 units

7 0
2 years ago
Solve for r in terms of s, t, and u. <br> t=u-s+r
Verdich [7]

Answer:

r = t - u - s

Step-by-step explanation:

To solve for r in terms of s, t, and u, means to have r on one side and have t, u, and s.

t = u - s + r

t - u = s + r

t - u - s = r

6 0
2 years ago
Hello again! This is another Calculus question to be explained.
podryga [215]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Functions

  • Function Notation
  • Exponential Property [Rewrite]:                                                                   \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Property [Root Rewrite]:                                                           \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

We are given the following and are trying to find the second derivative at <em>x</em> = 2:

\displaystyle f(2) = 2

\displaystyle \frac{dy}{dx} = 6\sqrt{x^2 + 3y^2}

We can differentiate the 1st derivative to obtain the 2nd derivative. Let's start by rewriting the 1st derivative:

\displaystyle \frac{dy}{dx} = 6(x^2 + 3y^2)^\big{\frac{1}{2}}

When we differentiate this, we must follow the Chain Rule:                             \displaystyle \frac{d^2y}{dx^2} = \frac{d}{dx} \Big[ 6(x^2 + 3y^2)^\big{\frac{1}{2}} \Big] \cdot \frac{d}{dx} \Big[ (x^2 + 3y^2) \Big]

Use the Basic Power Rule:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} (2x + 6yy')

We know that y' is the notation for the 1st derivative. Substitute in the 1st derivative equation:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 6y(6\sqrt{x^2 + 3y^2}) \big]

Simplifying it, we have:

\displaystyle \frac{d^2y}{dx^2} = 3(x^2 + 3y^2)^\big{\frac{-1}{2}} \big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]

We can rewrite the 2nd derivative using exponential rules:

\displaystyle \frac{d^2y}{dx^2} = \frac{3\big[ 2x + 36y\sqrt{x^2 + 3y^2} \big]}{\sqrt{x^2 + 3y^2}}

To evaluate the 2nd derivative at <em>x</em> = 2, simply substitute in <em>x</em> = 2 and the value f(2) = 2 into it:

\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = \frac{3\big[ 2(2) + 36(2)\sqrt{2^2 + 3(2)^2} \big]}{\sqrt{2^2 + 3(2)^2}}

When we evaluate this using order of operations, we should obtain our answer:

\displaystyle \frac{d^2y}{dx^2} \bigg| \limits_{x = 2} = 219

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

5 0
2 years ago
(30 POINTS AND BRAINLIEST) Show all work to solve 3x^2 + 5x − 2 = 0.
Dahasolnce [82]

Answer:

The answer to your question is:    (x + 2)(3x - 1) = 0

x1 = -2

x2 = 1/3

Step-by-step explanation:

                                           3x² + 5x − 2 = 0

Multiply 3 x -2 = -6

Find two numbers that added = +5 and multiply -6

These numbers are +6  and -1

Then:

                                           3x² + 6x -1x − 2 = 0

Factorize                           3x (x + 2) - 1(x + 2) = 0

Factorize again                (x + 2)(3x - 1) = 0

Finally

                         x + 2 = 0               3x - 1 = 0

                         x = -2                     x = 1/3

                                                   

5 0
3 years ago
What is the answer to this problem 1.5(x + 4) – 3 = 4.5(x – 2)?
erastova [34]

Answer:

x = 4

Step-by-step explanation:

1.5(x + 4) – 3 = 4.5(x – 2)

Distributive property

1.5x + 6 - 3 = 4.5x - 9

1.5x + 3 = 4.5x - 9

1.5x - 4.5x = -9 -3

-3x = -12

  x = 4

7 0
3 years ago
Read 2 more answers
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