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elena-s [515]
2 years ago
10

In a law office, the average number of billed hours per day was 150 last year. In the first 85 days of this year, the average nu

mber of billed hours per day is 158 with a standard deviation of 65 hours. When testing the hypothesis (at the 10% level of signficance) that the average number of billed hours per day has increased, what is the null and alternative hypotheses (please write out the null and alternative hypotheses below AND on your scratch work...failure to do BOTH will result in 0 points)
Mathematics
1 answer:
BigorU [14]2 years ago
6 0

Answer:

There isn't enough evidence to reject H0

Step-by-step explanation:

Null hypothesis :

H0: μ = 150

H1 : μ > 150

Decision region :

Reject Null if ;

Pvalue < α

Zstatistic = (x - μ) / (s/sqrt(n))

Zstatistic = (158 - 150) / (65/sqrt(85))

Zstatistic = 0.1135

Using the P value calculator from Zstatistic at 90% ; α = 0.10 confidence interval ; one tailed test = 0.128

Pvalue = 0.128

Since ; 0.128 > 0.10

Pvalue > α

We cannot reject H0:

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Solve the following equation for y: 35x - 7y = 49, what is the slope?
agasfer [191]

Answer:

y = 5x - 7

slope = 5

Step-by-step explanation:

35x - 7y = 49

Subtract 35x from both sides.

-7y = -35x + 49

Divide both sides by -7.

y = 5x - 7

The equation is now in the slope-intercept form, y = mx + b, where m is the slope.

slope = m = 5

4 0
2 years ago
What equation is graphed in this figure?
Ksivusya [100]

to get the equation of any straight line, we simply need two points off of it, let's use those two points in the picture below.

(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{3}{1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_2}{5}=\stackrel{m}{3}(x-\stackrel{x_2}{1})

keeping in mind that for the point-slope form, either point will do, in this case we used the second one, but the first one would have worked just the same.

7 0
1 year ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
Ppppppppppllllllllls I need helppppppp​
Phantasy [73]

Answer:

ΔABC≅ΔDEC by AAS

Step-by-step explanation:

You can use the AAS method of congruency.

Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent

Hope this helped.

5 0
2 years ago
maria threw a party for the promotion she received the party cost $20 for two people if she invited 20 guest what would be the c
zhenek [66]

The total cost would  be:

$20 = two people- 2*20=40$

20 = guest

20*20=

400 would be the cost

6 0
3 years ago
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