Given the data from the question, reaction 2 is 2.83 times faster compared to reaction 1
<h3>Data obtained from the question</h3>
- Molarity of reaction 1 (R₁) = 0.180 mol/L
- Molarity of reaction 2 (R₂) = 0.510 mol/L
- Comparison =?
<h3>How to determine the comparison of reaction 2 to reaction 1</h3>
We can determine how many times faster is reaction 2 to reaction by doing the following:
R₂ / R₁ = 0.510 / 0.180
R₂ / R₁ = 2.83
Cross multiply
R₂ = 2.83 × R₁
From the above illustration, we can see that reaction 2 is 2.83 times faster than reaction 1
Learn more about Graham's law of diffusion:
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Answer:
b. 6|x|
Step-by-step explanation:
√(36x²) = √36√(x²)= 6|x|
Because √ from the number can be only positive.
<h3>Answer: d. w = -6</h3>
The answer the 3,
First you have to apply the exponent rule which is 1 - 3• 1/g
Then you multiply the fractions - 1•3/g
Then multiply the numbers 1 and 3, which is 3, so there you have it 3/g, or 3, they’re the same thing.
