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neonofarm [45]
3 years ago
15

FREE BRAINLIEST pick a number, 1 or 2

Mathematics
2 answers:
Marianna [84]3 years ago
4 0

Step-by-step explanation:

1. jjejejejejej jejejekwkwkwkwk

nignag [31]3 years ago
4 0
Ummmm i pick 2 :)))
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HELP ME PLEASE WITH 1,2 AND 3 PLEASE DON'T TAKE LONG TO RESPOND !!​
soldi70 [24.7K]

Answer:

1. -19x

3. 23 -  8x

5. -18x + 2y

Step-by-step explanation:

first: 3x - x = 2x

2x - 22x = -20x

-20x + x = -19x

second one:

8 - (-15) = 23

12x - 20x = -8 x

23 - 8x

third:

-10x - 8x = -18x

3y - y = 2y

-18x + 2y

6 0
2 years ago
Read 2 more answers
Ramiro brought home ten pounds of rice to add to the 24 ounces of rice he had in the pantry. Let x represent the amount of rice
lianna [129]
16 ounces in a pound.
24 oz= 1.5 ibs.
Added to 10 ibs.
Now has 11.5 ibs.

R(x)= 11.5 - x
3 0
3 years ago
Read 2 more answers
-2(7 – y) +4= -4<br> How do you solve this
finlep [7]
The answer to this question is y=3
5 0
3 years ago
Read 2 more answers
During a sale at a bookstore, a customer buys one book at full price. The customer is given a 25 percent discount on a second bo
RoseWind [281]
Amount paid for the first book is $17.

Amount paid for the second book is 0.75 x 8 = $6

Total amount paid = $17 + $6 = $23

Total full cost of the two books = $17 + $8 = $25

Amount of discount = $25 - $23 = $2

% reduction = \frac{2}{25} \times100\%=8\%

Therefore, the <span>percent of the total cost of the two books reduced during the sale</span> is 8%
6 0
3 years ago
Read 2 more answers
If the numbers 4, 5 and 6 are each used exactly once to replace the letters in the expression A ( B − C ), what is the least pos
guapka [62]

Answer:

The least possible result is <em>-10</em>.

Step-by-step explanation:

Given the numbers 4, 5 and 6 are to be chosen one of the letters A, B or C.

First of all,

Let A = 4, B = 5 and C = 6

A(B-C) = 4 \times (5-6) = 4 \times -1 = -4

Let A = 4, B = 6 and C = 5

A(B-C) = 4 \times (6-5) = 4 \times 1 = 4

Let A = 5, B =4 and C = 6

A(B-C) = 5 \times (4-6) = 5 \times -2 = -10

Let A = 5, B = 6 and C = 4

A(B-C) = 4 \times (6-4) = 4 \times 2 = 8

Let A = 6, B = 4 and C = 5

A(B-C) = 6 \times (4-5) = 6 \times -1 = -6

Let A = 6, B = 5 and C = 4

A(B-C) = 6 \times (6-5) = 6 \times 1 = 6

Summarizing the above values in the form of a table:

\begin{center}\begin{tabular}{ c c c c}A & B & C & A(B-C)\\ 4 & 5 & 6 & -4\\  4 & 6 & 5 & 4\\  5 & 4 & 6 & -10\\  5 & 6 & 4 & 10\\  6 & 4 & 5 & -6\\ 6 & 5 & 4 & 6\end{tabular}\end{center}

So, the least possible result is <em>-10</em>.

3 0
3 years ago
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