Hello,
The median of the temperatures at Springwood is 86. (median is at the middle).
the median of the temperatures at Meadows is 73. (median is at the middle).
The (IQR) interquartile range of the temperatures at Meadows is 12. (You have to subtract both of the IQR left and right 80 - 68 = 12).
The (IQR) interquartile range of the temperatures at Springwood is 14. (You have to subtract both of the IQR left and right 91 - 77 = 14).
the difference of the medians as a multiple of their average interquartile range is 79.5 is average median and 13 average IQR.
64 square inches
hope this helps!
To get this, you need to divide 15/16 by 1/16. To do it, multiply 15/16 by 16 and you get 15 as your answer.
Answer:
sqrt(1 - 36/49) = +root(13)/7
Step-by-step explanation:
sin^2t + cos^2t is identical to 1 for all t.
(6/7)^2 + cos^2t = 1
1 - 36/49 = cos^2t
hence plus/miuns sqrt(1 - 36/49) = cos(t)
since t is acute, the answer must be positive.
Answer:
6
Step-by-step explanation:
Her profit will increase be 6 dollars.
x = 1
y = 45(1)
y = 45
