6 and 4. The answer has to be 20 characters long in order to post so ignore this part.
Answer:
y = 0.9x - 0.8
Step-by-step explanation:
First you use the formula m = (y2-y1) / (x2-x1)
Sub in the 2 points you are given and you get m = (-8-1) / (-8-2)
m = -9/-10 = 9/10
Now u use the point slope formula, (y - y1) = m(x - x1)
Sub in the points and you get (y - 1) = 9/10 (x-2)
Expand it out to get y - 1 = 9/10x - 18/10
multiple everything by 10 = 10y - 10 = 9x -18
make y the subject, 10y = 9x - 8
y = 0.9x - 0.8
Answer:
The measure of arc SQ is 95° ⇒ (1)
Step-by-step explanation:
- The measure of any circle is 360°
- The measure of the subtended arc to an inscribed angle is twice the measure of this angle
In the given circle
∵ S lies on the circumference of the circle
∴ ∠QSR is an inscribed angle
∵ ∠QSR is subtended by arc QR
→ By using the 2nd rule above
∴ m arc QR = 2 × m∠QSR
∵ m∠QSR = 95°
∴ m arc QR = 2 × 95
∴ m arc QR = 190°
→ By using the 1st rule above
∵ m of the circle = m arc QR + m arc SQ + m arc SR
∵ m arc SR = 75° and m arc QR = 190°
→ Substitute them in the equation above
∴ 360 = 190 + m arc SQ + 75
→ Add the like term in the right side
∴ 360 = 265 + m arc QS
→ Subtract 265 from both sides
∵ 360 - 265 = 265 - 265 + m arc SQ
∴ 95° = m arc SQ
∴ The measure of arc SQ is 95°
Answer:
the answer is 5 1/9 inches per month (answer)
Step-by-step explanation:
I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
