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Vladimir79 [104]
3 years ago
5

How do you illustratequadratic equationin one variable?​

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
4 0

Step-by-step explanation:

Quadratic Equation

Quadratic equation is in the form

ax2+bx+c=0

Where

a, b, & c = real-number constants

a & b = numerical coefficient or simply coefficients

a = coefficient of x2

b = coefficient of x

c = constant term or simply constant

a cannot be equal to zero while either b or c can be zero

Examples of Quadratic Equation

Some quadratic equation may not look like the one above. The general appearance of quadratic equation is a second degree curve so that the degree power of one variable is twice of another variable. Below are examples of equations that can be considered as quadratic.

1. 3x2+2x−8=0

2. x2−9=0

3. 2x2+5x=0

4. sin2θ−2sinθ−1=0

5. x−5x−−√+6=0

6. 10x1/3+x1/6−2=0

7. 2lnx−−−√−5lnx−−−√4−7=0

For us to see that the above examples can be treated as quadratic equation, we take example no. 6 above, 10x1/3 + x1/6 - 2 = 0. Let x1/6 = z, thus, x1/3 = z2. The equation can now be written in the form 10z2 + z - 2 = 0, which shows clearly to be quadratic equation.

Roots of a Quadratic Equation

The equation ax2 + bx + c = 0 can be factored into the form

(x−x1)(x−x2)=0

Where x1 and x2 are the roots of ax2 + bx + c = 0.

Quadratic Formula

For the quadratic equation ax2 + bx + c = 0,

x=−b±b2−4ac−−−−−−−√2a

See the derivation of quadratic formula here.

The quantity b2 - 4ac inside the radical is called discriminat.

• If b2 - 4ac = 0, the roots are real and equal.

• If b2 - 4ac > 0, the roots are real and unequal.

• If b2 - 4ac < 0, the roots are imaginary.

Sum and Product of Roots

If the roots of the quadratic equation ax2 + bx + c

= 0 are x1 and x2, then

Sum of roots

x1+x2=−ba

Product of roots

x1x2=ca

You may see the derivation of formulas for sum and product of roots here.

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What is the factored form of 6n4 – 24n3 + 18n?
seropon [69]

Answer: Its factored form will be

6n(n-1)(n^2-3n-3)

Step-by-step explanation:

Since we have given that

6n^4-24n^3+18n

So, we need to factor ,

6n(n^3-4n^2+3)

Now,

\text{Let }p(n)=n^3-4n^2+3

Now, by hit and trial method, we put n=1,

p(1)=1^3-4\times1^2+3=1-4+3=1-1=0

n=1\\n-1=0

So, n-1 is also factor of p(n).

Now,

\frac{n^3-4n^2+3}{n-1}=n^2-3n-3

So, its factored form will be

6n(n-1)(n^2-3n-3)

8 0
3 years ago
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|
alekssr [168]

Answer: the answer is infinite solutions

Step-by-step explanation:Systems of Equations Level 1:

Question 1

Two linear equations are given below.

Exactly how many solutions does this system of equations have?

Select one:

4 0
3 years ago
PLZ
g100num [7]

Answer:

21 pairs of socks

Step-by-step explanation:

We can find out how much money Chang has to spend on socks by subtracting the price of sneakers from his total money to spend by solving 160 - 95. From that, we get our answer of $65 that Chang has to spend on socks. We can divide 65 by 3 to see how many pairs of socks he can buy and we get our answer of 21 pairs of socks.

(sorry if it's confusing but I hope it helped anyway)

8 0
2 years ago
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Wangari plants trees at a constant rate of 12 trees every 3 hours. Write a equation that relates p, the number of trees Wangari
stealth61 [152]

Answer:

4h=p

Step-by-step explanation:

This is the answer because if both the number of trees and hours is divided by three, you get 4 trees per hour. So it's 4 times (h) equals total amount of trees planted.

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3 years ago
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What number is 10% of 42
vampirchik [111]

Answer:

4.2

Step-by-step explanation:

10% of 42 is 4.2

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3 years ago
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