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weeeeeb [17]
2 years ago
15

What are the values of x and y​

Mathematics
2 answers:
Illusion [34]2 years ago
8 0
- .... . / --. .. .- -. - / .... --- .-. ... . / -.-. --- -.-. -.- / .-- . .. --. .... - ... / --- ...- . .-. / .---- .---- / .--. --- ..- -. -.. ...
kaheart [24]2 years ago
5 0

Answer:

x = 10, y = 12

Step-by-step explanation:

There is a 2:1 ratio between 16 and 8, alternate side lengths.

2x = 20

x = 10

2(6) = y

y = 12

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Seven increased by the<br> product of two numbers
Kobotan [32]

Answer: x ≥ 5

Step-by-step explanation:

7 is increased by the product of a number and 3:  7 + 3x

Is at least 22:  ≥ 22

 

Your equation is: 7 + 3x ≥ 22

subtract 7 from both sides

3x ≥ 15

divide both sides by 3

x ≥ 5

8 0
3 years ago
What is going on<br>I am confused ​
nikdorinn [45]
?????? what do you mean
6 0
3 years ago
Read 2 more answers
1) Complete the following items dealing with sets.
Ivanshal [37]
From the set {21, 37, 45}, use substitution to determine which value of x makes the inequality true.x - 8 > 29 
45 
none of these 
37 
21From the set {21, 37, 45}, use substitution to determine which value of x makes the inequality true.x - 8 > 29 
45 
none of these 
37 
21
3 0
3 years ago
Thea has a key on her calculator marked $\textcolor{blue}{\bf\circledast}$. If an integer is displayed, pressing the $\textcolor
worty [1.4K]

Answer:

$9$

Step-by-step explanation:

Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.

To find: number that Thea originally entered

Solution:

The final number is $243$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $243$ must be $324$.

As previously the number was squared, so the number before $324$ must be $18$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $18$ must be $81$

As previously the number was squared, so the number before $81$ must be $9$.

3 0
3 years ago
Please help me with this
kaheart [24]

Answer:

m9 = 115

m4 =110

m10=65

m11= 70

m8= 70

m5 = 65

m3 = 70

m14 = 115

4 0
3 years ago
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