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2 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics

2 answers:

klemol [59]2 years ago

6 0

Answer:

-9p+3

plz mark me as brainliest

valentina_108 [34]2 years ago

3 0

If dont know how to solve things, feel free to download cymath :) this is not promoting im just helping people

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Harry church borrowed 17,500.00 at 6.5% exact interest. He had to pay back a maturity value of 17,873.97 to pay off the loan. Wh

kirill [66]

Answer:the term of the loan is approximately 4 months

Step-by-step explanation:

The term of the loan means the period for which the loan was given.

We would apply the formula for simple interest which is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

From the information given

P = 17500

R = 6.5%

I = total amount paid - principal

I = 17,873.97 - 17,500.00 = 373.97

Therefore

373.97 = (17500 × 6.5 × T)/100

373.97 = 1137.5T

T = 373.97/1137.5

T = 0.32 years

Converting to months, it becomes

0.32 × 12 = 3.84

Approximately 4 months.

3 0

3 years ago

Sal recorded the number of crackers in each snack-sized package he opened. Which statement must be true according to the box plo

Marina CMI [18]

Answer:

The data is skewed, and the lowest number of crackers in a package was 7

Step-by-step explanation:

Hi,

First of all, since the question was incomplete due to the missing capture of the range shown on the box plot. I attached it for you so I could answer your question as well.

Taking into consideration the attached image's information, symmetric would be right down the middle, but it is not.

The image shows that it is <em>positively skewed with the lowest number being 7.</em>

7 0

3 years ago

Read 2 more answers

What’s this <br> hdhshxbbsncjdkckskxbsh

7nadin3 [17]

Answer:

i dunno what that means but i think maybe your keyboard broke so the type of letters is random??

5 0

3 years ago

Jessie estimates the weight of her cat to be 10 pounds. The actual weight of the cat is 13.75 pounds. find the percent error.

romanna [79]

Answer:

$\large \boxed{27 \, \%} }$

Step-by-step explanation:

$\begin{array}{rcl}\text{Percent error}&= &\dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \,\%\\\\& = & \dfrac{\lvert 10 - 13.75\lvert}{13.75} \times 100 \, \% \\\\& = & \dfrac{\lvert -3.75\lvert}{13.75} \times 100 \, \%\\ \\& = & \dfrac{3.75}{13.75} \times 100 \,\%\\\\& = & 0.27 \times 100 \, \%\\& = & \mathbf{27 \, \%}\\\end{array}\\\text{The percent error is $\large \boxed{\mathbf{27 \, \%} }$}$

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2 years ago

Please help with this, thank you!

dezoksy [38]

Step-by-step explanation:

$\sqrt{1.8 \times \sin(46 ) \div 7.8 {}^{2} } - 50.8 \\ \sqrt{1.8} \times 0.72 \div 60.84 - 50.8 \\ \sqrt{1.29 \div 10.04 } \\ \sqrt{0.128 } \\ 0.358$

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3 years ago