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crimeas [40]
3 years ago
5

Need help ASAP please

Mathematics
2 answers:
SVEN [57.7K]3 years ago
3 0

Answer:

(2, 5) is the correct answer.

Serggg [28]3 years ago
3 0
Yes that’s right cool up
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The team must score an additional 6 points to win the game. There are 10 more chances to score one point.
Gnoma [55]
The team can miss no more than (less than or equal to) 4 chances to score a point.
4 0
4 years ago
Geometry Question: BK bisects angle ABC and M angle ABK=28.3 degrees. Find M angle KBC and M angle ABC.
GarryVolchara [31]

Answer:

KBC = 28.3

ABC = 56.6

Step-by-step explanation:

Given

ABK = 28.3

Required

Determine KBC and ABC

Since BK bisects ABK, then

KBC = ABK

Substitute 28.3 for ABK

KBC = 28.3

Using same point as above

<em>Since BK bisects ABK, then</em>

ABC = ABK + KBC

ABC = 28.3 + 28.3

ABC = 56.6

7 0
3 years ago
Can someone please help me with this thank u
MrRa [10]

Answer:option 3

Step-by-step explanation:

5 0
3 years ago
There are 255 students this term completing this same assignment. Assuming they calculated the CI correctly, how many students s
andrey2020 [161]

Answer:

The number of students we expect to have an interval that does not contain the true mean value is,  255\times [\alpha\%].

Step-by-step explanation:

A [100(1 - α)%] confidence interval for true parameter implies that if 100 confidence intervals are created then [100(1 - α)] of these 100 confidence intervals will consist the true population parameter value.

Here α is the significance level. It is defined as the probability rejecting the claim that the true parameter value is not included in the 100(1 - α)% confidence interval.

It is provided that 255 students create the same confidence interval, correctly.

Then the number of students we expect to have an interval that does not contain the true mean value is,  255\times [\alpha\%]

For instance, if the students are creating a 95% confidence interval for mean then the number of students we expect to have an interval that does not contain the true mean will be:

The significance level is:

Confidence\ level=100(1-\alpha)\\\frac{95}{100}=(1-\alpha)\\\alpha =1-0.95=0.05

Number of students we expect to have an interval that does not contain the true mean will be: 255\times [\alpha\%]=255\times 0.05=12.75\approx13

Thus, 13 of the 255 confidence intervals will not consist the true mean value.

3 0
3 years ago
Josh worked 50 hours frank worked 50 hours less and twice as many hours as josh did. How many hours did frank work
blondinia [14]

Answer:

50 hours

Step-by-step explanation:

Josh = 50 hours

frank worked 50 hours less and twice as many hours as josh did.

Frank = 2(Josh) - 50 hours

= 2(50 hours) - 50 hours

= 100 hours - 50 hours

= 50 hours

Therefore, Frank worked for 50 hours

7 0
3 years ago
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