The team can miss no more than (less than or equal to) 4 chances to score a point.
Answer:


Step-by-step explanation:
Given

Required
Determine KBC and ABC
Since BK bisects ABK, then

Substitute 28.3 for ABK

Using same point as above
<em>Since BK bisects ABK, then</em>



Answer:option 3
Step-by-step explanation:
Answer:
The number of students we expect to have an interval that does not contain the true mean value is,
.
Step-by-step explanation:
A [100(1 - α)%] confidence interval for true parameter implies that if 100 confidence intervals are created then [100(1 - α)] of these 100 confidence intervals will consist the true population parameter value.
Here α is the significance level. It is defined as the probability rejecting the claim that the true parameter value is not included in the 100(1 - α)% confidence interval.
It is provided that 255 students create the same confidence interval, correctly.
Then the number of students we expect to have an interval that does not contain the true mean value is, ![255\times [\alpha\%]](https://tex.z-dn.net/?f=255%5Ctimes%20%5B%5Calpha%5C%25%5D)
For instance, if the students are creating a 95% confidence interval for mean then the number of students we expect to have an interval that does not contain the true mean will be:
The significance level is:

Number of students we expect to have an interval that does not contain the true mean will be: ![255\times [\alpha\%]=255\times 0.05=12.75\approx13](https://tex.z-dn.net/?f=255%5Ctimes%20%5B%5Calpha%5C%25%5D%3D255%5Ctimes%200.05%3D12.75%5Capprox13)
Thus, 13 of the 255 confidence intervals will not consist the true mean value.
Answer:
50 hours
Step-by-step explanation:
Josh = 50 hours
frank worked 50 hours less and twice as many hours as josh did.
Frank = 2(Josh) - 50 hours
= 2(50 hours) - 50 hours
= 100 hours - 50 hours
= 50 hours
Therefore, Frank worked for 50 hours