Answer:Question 135184: Find the equation of the line with slope 6 that goes through the point (6,4). Write your answer in slope-intercept form. b=-32 ANSWER FOR THE Y INTERCEPT. Y=6X-32 LINE EQUATION
Step-by-step explanation:
A negative number is not considered a whole number...so ur answer is -229
Answer:
y=2x+7
Step-by-step explanation:
When an equation is parallel to another, it shares the same slope.
Our original line is y=2x-8, and it is in slope-intercept form (y=mx+b)
This means that our slope is 2 because m represents the slope.
The slope of our parallel line will then also be 2.
<u>We can begin to plug that into point-slope form which is:</u>
y - y1 = m(x - x1)
This is where (x1, y1) is a point the line intersects, and m is the slope.
<u>Plugging in the slope, we'll have:</u>
y - y1 = 2(x - x1)
We also know it intersects the point (-4, -1）
We can plug this into our equation as well.
y - (-1) = m(x - (-4))
y+1=2(x+4)
<u>Now, we can simplify it into slope-intercept form:</u>
y+1=2(x+4)
Distribute
y+1=2x+8
Subtract 1 from both sides
y=2x+8-1
y=2x+7
Answer:
Proofs are in the explantion.
Step-by-step explanation:
We are given the following:
1) 
for integer 
.
1) 
for integer 
.
a)
Proof:
We want to show 
.
So we have the two equations:
a-b=kn and c-d=mn and we want to show for some integer r that we have
(a+c)-(b+d)=rn. If we do that we would have shown that .
kn+mn = (a-b)+(c-d)
(k+m)n = a-b+ c-d
(k+m)n = (a+c)+(-b-d)
(k+m)n = (a+c)-(b+d)
k+m is is just an integer
So we found integer r such that (a+c)-(b+d)=rn.
Therefore, .
//
b) Proof:
We want to show 
.
So we have the two equations:
a-b=kn and c-d=mn and we want to show for some integer r that we have
(ac)-(bd)=tn. If we do that we would have shown that .
If a-b=kn, then a=b+kn.
If c-d=mn, then c=d+mn.
ac-bd = (b+kn)(d+mn)-bd
= bd+bmn+dkn+kmn^2-bd
= bmn+dkn+kmn^2
= n(bm+dk+kmn)
So the integer t such that (ac)-(bd)=tn is bm+dk+kmn.
Therefore, .
//
