If repeated sample sizes of large sizes are taken at random, and proportion P is calculated for samples the sample mean will have a normal distribution irrespective of the original distribution.

In other words, the sample proportion will follow a normal distribution with mean = p-hat and std deviation = $\sqrt{\frac{p(1-p)}{n} }$

This is a direct corrollary of central limit theorem for sample means.

Hence we have irrespective of sample size, sample proportion will have expected value same as p-hat.

So whether sample size is 500 or 100 the p hat will have the same distribution.

8 0

4 years ago

answer both questions to get brain ( if u cant see all the answers its fine all u need is the question)

Flauer [41]

Answer:

1.A

2.C

Step-by-step explanation:

3 0

4 years ago

Hi I need help for my math class it’s due Saturday!

vichka [17]

Answer:

a) 21m - 0.87 = m

b) m = 0.0435 mg

21(0.0435) - 0.87 = 0.0435

0.9135 - 0.87 = 0.0435

0.0435 = 0.0435

True statement, so correct

c) 21m - 0.87 = m

20m = 0.87

m = 0.87/20

m = 0.0435 mg

4 0

3 years ago

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