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Mnenie [13.5K]
3 years ago
15

HEY PLEASE HELP. The student's savings box had accumulated 35 twenty and fifty cent coins in one month, in the total amount of 1

0.3 euros. Several 20 and several 50 cent coins are in the box.
Mathematics
1 answer:
stira [4]3 years ago
6 0

Answer: 11 and 24

Step-by-step explanation:

Given

There are 35- 50 cents and 20 cents coins

The total of them is 10.3 euros

Suppose no of 50 cents coins is x and 20 cents is y

so we can write

\Rightarrow 0.5x+0.2y=10.3\quad \ldots(i)

Also,

\Rightarrow x+y=35\quad \ldots(ii)

Solving (i) and (ii) we get

x=11; y=24

There are 11 fifty cent and 24 twenty cents coins

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Which of the tables represents a function? (5 points)
AlladinOne [14]

Answer:

It's table D

Step-by-step explanation:

I just took the test.

3 0
2 years ago
A survey of 700 adults from a certain region​ asked, "What do you buy from your mobile​ device?" The results indicated that 59​%
Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are  (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes n_{1} = 400 and n_{2} = 300

Proportion of mean p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

<u>Alternative hypothesis H1:</u>- p1 ≠ p2

a) The test statistic is

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }

where p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}  

on calculation we get   p = 0.56    

now q =1-p = 1-0.56=0.44

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }\\   =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300}   }

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

<u>conclusion</u>:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals  (0.523 ,0.596)</u>

<u></u>

3 0
3 years ago
Given the two expressions below: 1) 4x2 − 8x + 9 2) 3x2 + 2y + 6 Is the sum of the two expressions above a polynomial? Why or wh
Mkey [24]
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Note that despite it's name, single constants, monomials, binomials, trinomials, and expressions with more than three terms are all polynomials.
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What makes an expression NOT a polynomial?
Expressions that contain non-integer or negative powers of variables, rational functions, infinite series.
For example,
sqrt(x+1), 1/x+4, 1+x+ x^2/2!+x^3/3!+x^4/4!+...., (5x+3)/(6x+7)
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8 0
3 years ago
Bdhskakaiaggsbsnasnbdbsjsjs simplify c^4/c^3
slava [35]

Answer:

Cancel the common factor of  c^ 4  and  c ^3 .

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Step-by-step explanation:

Hope this helps! Have a nice day!

5 0
2 years ago
Read 2 more answers
If 18 is added to a certain number and the sum is divided by 6, the result is 1 more than 14 of the original number. Find the or
Katyanochek1 [597]
The original number is 72 


(18+x)/6 = 1+14 
1/6x + 3 = 1 + 14 (Distribute)
1/6x + 3 = (1+14) (Combine Like Terms)
1/6x + 3 = 15 
        - 3 = -3          (Subtract 3 From Both Sides)
1/6x = 12 
(1/6x)*6 = 12 * 6  (Multiply Both Sides By 6)
x = 72


5 0
3 years ago
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