Answer:
-9
Step-by-step explanation:
8x-4=6x-10
2x-4=-10
2x=-6
x=-3
-3x3= -9
Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

So we apply chain rule:
=

Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
Any real number line ranges from negative infinity to positive infinity. A real number number line consists of all the rational and irrational numbers. Let us take three intervals which contain both the rational and irrational numbers.
First interval: [3,4]
Since every integer is a rational number, 3 and 4 are both rational. In this interval there occurs the value of π (3.14159..) which is an irrational number.
Second interval : [0,2]
0 and 2 are integers and hence are rational. In this interval, occurs √2 (1.41421...) is an irrational number.
Third interval : [2,3]
In this interval, Eulers number 'e' lie whose value is (2.718281.. )
Hence we can conclude that, there occurs an irrational number between any two rational number.
-3-4(5)
-4(5)=-20
-3-20
The answers is -23