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Anna007 [38]
3 years ago
7

A jar contains only​ pennies, nickels,​ dimes, and quarters. There are 21 ​pennies, 26 ​dimes, and 15 quarters. The rest of the

coins are nickels. There are 76 coins in all. How many of the coins are not​ nickels? If n represents the number of nickels in the​ jar, what equation could you use to find​ n?
Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

14

Step-by-step explanation:

21+26+15=62 72-62=14 :)

nekit [7.7K]3 years ago
7 0

Answer: The Answer is 62 coins

Step-by-step explanation:

If there are 76 coins in the jar in total,All you do is add all of the number of each coin there is except nickels and add it together. Then you take that amount away from the total number of coins to find out how many nickels are inside the jar.

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the smallest angle in a triangle is one-third of the largest angle. the third angle is 10degrees more than the smallest angle. f
Alex787 [66]
A: smallest 
c: largest
b: third 
a+b+c=180
a=c/3
b=10+a
solve it
a=34
b=44
c=102
5 0
3 years ago
If y=1/4 when x=5, find y when x=7, given that y directly with x
mariarad [96]

Answer:

7/20

Step-by-step explanation:

Since y varies directly with x, the ratio of y to x is proportional.

... y / 7 = (1/4)/(5)

... y / 7 = 1 / 20 . . . . simplify

... y = 7/20 . . . . . multiply by 7

3 0
4 years ago
jamal finished 5/6 of his homework .margaret finished 3/4 and steve finised 10/12 of his homeowrk. which 2 students finished the
Blababa [14]
Jamal and Steve finished the same amount of homework because 5/6 is the same as 10/12
7 0
3 years ago
Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so
IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14 \times c + 5 \times v=119

14c + 5v = 119 ------- eqn 1

<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10 \times c + 10 \times v = 130

10c + 10v = 130 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0
3 years ago
Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.
lakkis [162]

Answer:

2*sin(x)+y*cos(x)-cos(y)=C_1

Step-by-step explanation:

Let:

P(x,y)=2*cos(x)-y*sin(x)

Q(x,y)=cos(x)+sin(y)

This is an exact differential equation because:

\frac{\partial P(x,y)}{\partial y} =-sin(x)

\frac{\partial Q(x,y)}{\partial x}=-sin(x)

With this in mind let's define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x}=P(x,y)

and

\frac{\partial f(x,y)}{\partial y}=Q(x,y)

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y)

f(x,y)=\int\  2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}

Now, let's replace the previous result into \frac{\partial f(x,y)}{\partial y}=Q(x,y) :

cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)

Solving for \frac{dg(y)}{dy}

\frac{dg(y)}{dy}=sin(y)

Integrating both sides with respect to y:

g(y)=\int\ sin(y)  \, dy =-cos(y)

Replacing this result into f(x,y)

f(x,y)=2*sin(x)+y*cos(x)-cos(y)

Finally the solution is f(x,y)=C1 :

2*sin(x)+y*cos(x)-cos(y)=C_1

7 0
3 years ago
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