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Elena-2011 [213]
2 years ago
5

Please help

Mathematics
2 answers:
rosijanka [135]2 years ago
8 0

Answer:

B

Step-by-step explanation:

person above me is correct

aleksklad [387]2 years ago
6 0

Answer:

B

Step-by-step explanation:

The value of the 4 in 14.8 is 10 times the value of the 4 in 3.46.

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Miranda and cyndi start hiking from the same point. miranda hikes at a heading of , or due west, and cyndi hikes at a heading of
igomit [66]

They are both 6.9 miles apart after one hour if they both hike 4 miles/hour

The correct option is (B)

<h3>What is the triangle?</h3>

In terms of geometry, the triangle is a three-sided polygon with three edges and three vertices. The triangle's interior angles add up to 180°.

<h3>According to the given information:</h3>

Miranda and Cyndi start hiking from the same point. Miranda hikes at a heading of 270° or due west, and Cyndi hikes at a heading of 30°

<h3>From the isosceles triangle:</h3>

h = 4sin30

h = 4(1/2)

h = 2 miles

<h3>From Pythagoras theorem:</h3>

x² = 4² - h² = 4² - 2²

x = √12

x = 3.46 miles

Total distance = 2×3.46  = 6.9 miles

Thus, they are both 6.9 miles apart after one hour if they both hike 4 miles/hour option (B) 6.9 miles is correct.

Learn more about the triangle here:

brainly.com/question/25813512

#SPJ4

I understand that the question you are looking for :

Miranda and Cyndi start hiking from the same point. Miranda hikes at a heading of , or due west, and Cyndi hikes at a heading of , or n e. if they both hike 4 miles/hour, approximately how far apart are they after one hour?

A) 4.3 miles. .

B) 6.9 miles

C) 8.0 miles

D) 5.7 miles

4 0
1 year ago
At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu
V125BC [204]

Answer:

\frac{^3C_1\times ^4C_1}{^{12}C_2}

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

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Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = ^3C_1\times ^4C_1

Also, the total combination of choosing any 2 subjects out of 12 subjects = ^{12}C_2

Hence, the probability that a student chooses an art elective and a history elective = \frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}

=\frac{^3C_1\times ^4C_1}{^{12}C_2}

Which is the required expression.

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