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3 years ago

14

To calculate the maximum data rate in a line we use shannon's theorem: max data rate =bandwidth x log2 (1 + s/n) what is the max

imum data rate in a fiber optic line if the s/n=95 [db] and the bandwidth of the line is zero [mhz]?

1 answer:

Deffense [45]3 years ago

8 0

The maximum data rate on any line with zero bandwidth is zero.

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A building cast a shakedown that is 12 meters long.The distance from the top of the building to the top of the shadow is 20 mete

Alex Ar [27]

You would use pythagoras theorem which would be
16m

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3 years ago

At the movie theatre, child admission is $6.10 and adult admission is $9.90. On Friday, four times as many adult tickets as chil

Lena [83]

Answer:

26 child tickets

Step-by-step explanation:

4c = a to make the adult tickets equal to the child tickets multiply the child tickets by 4. then use substitution.

6.10c + 9.90(4c) = 1188.20

6.10c +39.6c = 1188.20

45.7c = 1188.20

c = 26

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3 years ago

A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas

WITCHER [35]

Answer:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

$P(A) = 0.8, P(B) = 0.2$

We are assuming that the two events are independent so then we have the following propert:

$P(A \cap B ) = P(A) * P(B)$

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

$P(B' \cup A')$

And using the De Morgan laws we know that:

$(A \cap B)' = A' \cup B'$

So then we can write the probability like this:

$P(B' \cup A') = P((A \cap B)')$

And using the complement rule we can do this:

$P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)$

Since A and B are independent we have:

$P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32$

And then our final answer would be:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

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3 years ago

Together, Steve and Tom sold 86 raffle tickets for their school. Steve sold 14 more than twice as many raffle tickets as Tom. Ho

bonufazy [111]

86= Steve + Tom

Steve= 14+2(Tom)

86= (14+2T) + T

86-14 = 3T

62 = T

Steve sold 62 tickets

86-62 = 24 tickets Tom sold

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3 years ago

Han began with 5/6 pound of modeling clay and used1/5 of the clay to make decorative magnets. she divides the remaining clay int

tatiyna

Each portion will weigh 0.079lbs.

5/6-1/5=?

.833-.2=.633

.633÷8=.079lbs.

8 0

3 years ago