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3 years ago

14

To calculate the maximum data rate in a line we use shannon's theorem: max data rate =bandwidth x log2 (1 + s/n) what is the max

imum data rate in a fiber optic line if the s/n=95 [db] and the bandwidth of the line is zero [mhz]?

1 answer:

Deffense [45]3 years ago

8 0

The maximum data rate on any line with zero bandwidth is zero.

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Writing in Slope-Intercept Form, 4 Ways <br><br> (3, 2) & (-3, -4)

andre [41]

Answer:

y = x +1

Step-by-step explanation:

y= mx + b

where m is the slope and b is the y-intercept

m = (y2-y1)/ (x2-x1) = 2+4 / 3+3 = 6/6 = 1

from the point -slope equation we have

y-y1 = m* (x-x1)

y-3 = 1* ( x-2)

y= x -2+3

y= x +1

so the slope m=1 and the y-intercept b=1

3 0

3 years ago

Solve the equation 2x^2-3x-6=0 give your answer correct to two decimal places

IRISSAK [1]

Answer:

<h2>x = - 1.14 or x = 2.64</h2>

Step-by-step explanation:

2x² - 3x - 6 = 0

Using the quadratic formula

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a}$

a = 2 , b = - 3 , c = 6

Substituting the values into the above formula

We have

$x = \frac{ - - 3± \sqrt{ { - 3}^{2} - 4(2)( - 6)} }{2(2)}$

$x = \frac{3± \sqrt{9 +48 } }{4}$

$x = \frac{3± \sqrt{57} }{4}$

$x = \frac{3 - \sqrt{57} }{4} \: \: \: \: or \: \: \: \: \: x = \frac{3 + \sqrt{57} }{4}$

We have the final answer as

<h3>x = - 1.14 or x = 2.64</h3>

Hope this helps you

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The ratio of boys to girls at a day care center is 5 to 4. which of the following cannot be the total number of children at the

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C: 60 children because 60 cannont go into 9 which is the amount of children in the first ratio

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A hole 8 feet deep because it’s down making it negative

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