Seventy-five million three hundred thousand two hundred seven
Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=

so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=

x=

x=

x=

x=

there are no real numbers that satisfy this
Answer:
(x+1)^2+(y-7)^2=8
Step-by-step explanation:
You should try the next one and I can check work or tell you if it is right.
The diameter length can be found be computing the distance that (-3,5) is to (1,9) which is sqrt(4^2+4^2)=sqrt(32).
The radius is half the diameter so it is sqrt(32)/2.
The center of the circle is the midpoint of a diameter. So compute the (Average of x, average of y)=(-1,7)
So plug into (x-h)^2+(y-k)^2=r^2 we get
(x+1)^2+(y-7)^2=32/4
simplifying gives
(x+1)^2+(y-7)^2=8
(I had to type this twice; my cat jump on my keyboard)
G, the y-intercept will not be 3