(a) getting the difference of outputs of any two inputs that are 1 unit apart, we have the following:
-3 – (-11) = 8
5 – (-3) = 8
13 – 5 = 8
21 – 13 = 8
29 – 21 = 8
37 – 29 = 8
45 – 37 = 8
53 – 45 = 8
(b) getting the difference of outputs of any two inputs that are 2 units apart, we have the following:
5 – (-11) = 16
13 – (-3) = 16
21 – 5 = 16
29 – 13 = 16
37 – 21 = 16
45 – 29 = 16
53 – 37 = 16
(c) getting the difference of outputs of any two inputs that are 3 units apart, we have the following:
13 – (-11) = 24
21 – (-3) = 24
29 – 5 = 24
37 – 13 = 24
45 – 21 = 24
53 – 29 = 24
(d) To get the ratio of the required problem, first we divide the first difference of outputs by one input interval, that is
8÷1=8
Next, we divide the second differences of outputs by two input intervals, that is
16÷2=8
Lastly, we divide the third differences of outputs by three input intervals, that is
24÷3=8
Notice that each ratio have the same result which is 8. This means that whatever the number input intervals are, between two outputs is 8 times apart.
Answer:
P(x < 3) = 0.42319
Step-by-step explanation:
From the given information:
The mean density 
3
Let x be the random variable that follows a Poisson distribution.
Therefore:
for x =1, 2, 3...
However, the probability that a random quadrat contains less than 3 spatuletails can be computed as:
P(x < 3) = 0.42319
1. x-2(2x-3.5)=-14
x-4x+7=-14
-3x=-21
x=7
2. y=2(7)-3.5
y=14-3.5
y=10.5
hope this helps!
Answer:
h + 5
Step-by-step explanation:
increased = add so yeah...
We know that the side lengths of the square base are: x * x. The volume is 12, so for now, let's say that y is the other side length. Then, x * x * y = 12. We can solve for y: y = 12/x^2. Now, we find the surface area of the 5 sides.
Four of the sides have the same area: x * (12/x^2) = 12/x, so we multiply this by 4: 48/x.
The last side is the base: x * x = x^2.
We add 48/x to x^2:
x^2 + 48/x
So, the answer is the fourth choice, (d).
